我如何创建此ActionLink的正确路径值？ [英] How do I create the correct route values for this ActionLink?

问题描述

SearchResults.aspx 的模型的实例 PersonSearch ;当一个新的页面请求到达（GET请求），操作方法应该把它和计算新的结果。

The Model of SearchResults.aspx is an instance of PersonSearch; when the request for a new page arrive (a GET request), the action method should take it and compute the new results.

[AcceptVerbs(HttpVerbs.Get)]
public ActionResult SearchResults(PersonSearch search, int? page)
{
    ViewData["Results"] = new PaginatedList<Person>(_searchService.FindPersons(search), page ?? 0, 1);
    return View("SearchResults", search);
}

然后我不得不产生previous /下一个链接：

Then I have to generate the previous/next links:

<%= Html.ActionLink("Next Page >", "SearchResults", routeValues) %>

如果我用 routeValues​​ = ViewData.Model 我可以看到对象属性传递的地址，但我不能添加页参数。

If I use routeValues = ViewData.Model I can see the object properties passed the address, but I can't add the "page" parameter.

推荐答案

据认为这将是更好地创造，而不是使用（并有可能改变目前的routevalues​​）用正确的价值观另一个对象：

It think it would be better to create another object with the correct values, instead of using (and potentially altering the current routevalues):

<%=Html.ActionLink("Next Page >", "SearchResults", new {
    search = this.Model,
    page = 1 //or whatever
}) %>

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