PBKDF2-HMAC-SHA2 测试向量 [英] PBKDF2-HMAC-SHA2 test vectors
问题描述
RFC6070 中有 PBKDF2-HMAC-SHA1 的测试向量.RFC4231 中有 HMAC-SHA2 的测试向量.
There are test vectors for PBKDF2-HMAC-SHA1 in RFC6070. There are test vectors for HMAC-SHA2 in RFC4231.
但到目前为止,我还没有在任何地方找到 PBKDF2-HMAC-SHA2 的测试向量.
But so far I haven't found test vectors for PBKDF2-HMAC-SHA2 anywhere.
我对 SHA256 最感兴趣,所以我将发布一些我用我的实现计算的向量.如果有人可以验证/确认他们,或者贡献他们自己的,我会很高兴.
I'm most interested in SHA256, so I'll post some vectors I calculated with my implementation. I'd be happy if someone could verify/confirm them, or contribute their own.
推荐答案
我 使用标准 hashlib 和 hmac Python 中的模块,并根据 RFC 6070 向量和 您发布的向量 - 匹配.
I implemented PBKDF2 using the standard hashlib and hmac modules in Python and checked the output against both the RFC 6070 vectors and the vectors you posted – it matches.
这是我使用较大的 dkLen
获得的向量,以匹配较大的摘要输出大小.这是pbkdf2-test-vectors.py sha256
的输出,运行大约需要10分钟.
Here are the vectors I get with a larger dkLen
to match the larger digest output size. This is the output of pbkdf2-test-vectors.py sha256
, which takes about 10 minutes to run.
PBKDF2 HMAC-SHA256 Test Vectors
Input:
P = "password" (8 octets)
S = "salt" (4 octets)
c = 1
dkLen = 32
Output:
DK = 12 0f b6 cf fc f8 b3 2c
43 e7 22 52 56 c4 f8 37
a8 65 48 c9 2c cc 35 48
08 05 98 7c b7 0b e1 7b (32 octets)
Input:
P = "password" (8 octets)
S = "salt" (4 octets)
c = 2
dkLen = 32
Output:
DK = ae 4d 0c 95 af 6b 46 d3
2d 0a df f9 28 f0 6d d0
2a 30 3f 8e f3 c2 51 df
d6 e2 d8 5a 95 47 4c 43 (32 octets)
Input:
P = "password" (8 octets)
S = "salt" (4 octets)
c = 4096
dkLen = 32
Output:
DK = c5 e4 78 d5 92 88 c8 41
aa 53 0d b6 84 5c 4c 8d
96 28 93 a0 01 ce 4e 11
a4 96 38 73 aa 98 13 4a (32 octets)
Input:
P = "password" (8 octets)
S = "salt" (4 octets)
c = 16777216
dkLen = 32
Output:
DK = cf 81 c6 6f e8 cf c0 4d
1f 31 ec b6 5d ab 40 89
f7 f1 79 e8 9b 3b 0b cb
17 ad 10 e3 ac 6e ba 46 (32 octets)
Input:
P = "passwordPASSWORDpassword" (24 octets)
S = "saltSALTsaltSALTsaltSALTsaltSALTsalt" (36 octets)
c = 4096
dkLen = 40
Output:
DK = 34 8c 89 db cb d3 2b 2f
32 d8 14 b8 11 6e 84 cf
2b 17 34 7e bc 18 00 18
1c 4e 2a 1f b8 dd 53 e1
c6 35 51 8c 7d ac 47 e9 (40 octets)
Input:
P = "pass word" (9 octets)
S = "sa lt" (5 octets)
c = 4096
dkLen = 16
Output:
DK = 89 b6 9d 05 16 f8 29 89
3c 69 62 26 65 0a 86 87 (16 octets)
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