PBKDF2-HMAC-SHA2测试载体 [英] PBKDF2-HMAC-SHA2 test vectors

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问题描述

RFC6070 中有针对PBKDF2-HMAC-SHA1的测试向量。 RFC4231 中有HMAC-SHA2的测试向量。

There are test vectors for PBKDF2-HMAC-SHA1 in RFC6070. There are test vectors for HMAC-SHA2 in RFC4231.

但是到目前为止,我还没有找到任何地方的PBKDF2-HMAC-SHA2的测试载体。

But so far I haven't found test vectors for PBKDF2-HMAC-SHA2 anywhere.

我最感兴趣的是SHA256,与我的实现。

I'm most interested in SHA256, so I'll post some vectors I calculated with my implementation. I'd be happy if someone could verify/confirm them, or contribute their own.

推荐答案

实现的PBKDF2 使用标准 hashlib hmac 模块,并检查了针对RFC 6070的输出向量和您发布的向量 - 它匹配。

I implemented PBKDF2 using the standard hashlib and hmac modules in Python and checked the output against both the RFC 6070 vectors and the vectors you posted – it matches.

这是我使用较大的 dkLen 来匹配较大的摘要输出大小的向量。这是 pbkdf2-test-vectors.py sha256 的输出,运行大约需要10分钟。

Here are the vectors I get with a larger dkLen to match the larger digest output size. This is the output of pbkdf2-test-vectors.py sha256, which takes about 10 minutes to run.

PBKDF2 HMAC-SHA256 Test Vectors

Input:
  P = "password" (8 octets)
  S = "salt" (4 octets)
  c = 1
  dkLen = 32

Output:
  DK = 12 0f b6 cf fc f8 b3 2c
       43 e7 22 52 56 c4 f8 37
       a8 65 48 c9 2c cc 35 48
       08 05 98 7c b7 0b e1 7b (32 octets)


Input:
  P = "password" (8 octets)
  S = "salt" (4 octets)
  c = 2
  dkLen = 32

Output:
  DK = ae 4d 0c 95 af 6b 46 d3
       2d 0a df f9 28 f0 6d d0
       2a 30 3f 8e f3 c2 51 df
       d6 e2 d8 5a 95 47 4c 43 (32 octets)


Input:
  P = "password" (8 octets)
  S = "salt" (4 octets)
  c = 4096
  dkLen = 32

Output:
  DK = c5 e4 78 d5 92 88 c8 41
       aa 53 0d b6 84 5c 4c 8d
       96 28 93 a0 01 ce 4e 11
       a4 96 38 73 aa 98 13 4a (32 octets)


Input:
  P = "password" (8 octets)
  S = "salt" (4 octets)
  c = 16777216
  dkLen = 32

Output:
  DK = cf 81 c6 6f e8 cf c0 4d
       1f 31 ec b6 5d ab 40 89
       f7 f1 79 e8 9b 3b 0b cb
       17 ad 10 e3 ac 6e ba 46 (32 octets)


Input:
  P = "passwordPASSWORDpassword" (24 octets)
  S = "saltSALTsaltSALTsaltSALTsaltSALTsalt" (36 octets)
  c = 4096
  dkLen = 40

Output:
  DK = 34 8c 89 db cb d3 2b 2f
       32 d8 14 b8 11 6e 84 cf
       2b 17 34 7e bc 18 00 18
       1c 4e 2a 1f b8 dd 53 e1
       c6 35 51 8c 7d ac 47 e9 (40 octets)


Input:
  P = "pass\0word" (9 octets)
  S = "sa\0lt" (5 octets)
  c = 4096
  dkLen = 16

Output:
  DK = 89 b6 9d 05 16 f8 29 89
       3c 69 62 26 65 0a 86 87 (16 octets)

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