将地址地理编码为iphone中的坐标 [英] geocoding address into coordinates in iphone

问题描述

我正在尝试使用以下代码将地址地理编码为坐标:

I am trying to geocode address into coordinates using following code:

CLGeocoder *geocoder = [[CLGeocoder alloc] init];
    [geocoder geocodeAddressString:@"6138 Bollinger Road, San Jose, United States" completionHandler:^(NSArray* placemarks, NSError* error){
                     for (CLPlacemark* aPlacemark in placemarks)
                     {
                         // Process the placemark.
                         NSString *latDest1 = [NSString stringWithFormat:@"%.4f",aPlacemark.location.coordinate.latitude];
                         NSString *lngDest1 = [NSString stringWithFormat:@"%.4f",aPlacemark.location.coordinate.longitude];
                         lblDestinationLat.text = latDest1;
                         lblDestinationLng.text = lngDest1;
                     }
                 }];

我已经尝试了很多次，但调试器从不进入块，我无法获得位置.有人可以帮我吗?

I have tried it many times but the debugger never enters the block and I am not able to get the location. Can someone please help me with it?

问候
潘卡伊

推荐答案

好吧，我发现我的错误了.代码是正确的并且工作完美.我一直在通过调试器处理它，并试图找出调试器没有进入块的原因.但是现在我发现调试器此时没有进入该块.获取位置值所需的时间很少.它是异步完成的，因此我无法找到它，并且由于崩溃后没有值而导致崩溃.我已将代码发布块移到块内，现在一切正常.

All right I found my mistake. The code is correct and works perfect. All the while I was working on it was through debugger and was trying to figure out why the debugger did not enter the block. But now I have found out debugger does not enter the block at that moment. It takes little in getting the location values. It is done asynchronously so I was not able to find it and I was getting crash because of no values just after the crash. I have moved my code post block to inside the block and everything works fine for me now.

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