iPhone iOS5 CLGeocoder如何对大(200)个地址进行地理编码? [英] iPhone iOS5 CLGeocoder how to geocode a large (200) set of addresses?

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问题描述

我得到了大约200个地址,我需要知道它们的纬度和经度。我已经创建了一个解析地址的方法,现在我正在尝试使用 CLGeocoder 获取这些地址的坐标。

I got a large set of about 200 addresses for which I need to know their latitude and longitude. I've created a method that parses the addresses, and now I'm trying to get coordinates for these addresses using CLGeocoder.

我目前的做法是并行创建地理编码器,让他们发挥魔力。我注意到他们每个人似乎都采取了一个单独的线程。 (所以我在一个点上看到多达100个线程)。

My current approach is to create geocoders in parallel and let them do their magic. I noticed that each one of them seems to take a separate thread. (so I saw up to 100 threads at one point).

我遇到的问题是在某个时刻(大约50个地址之后) ,地理编码停止返回任何地方标记,

NSLog(@"Address not recognized: *%@*",[htc objectForKey:kAddressKey]);

被调用。这是对多个线程或内置CLGeocoder限制的限制吗?可能是因为我没有正确清理地理编码器并需要某种自动释放声明(ARC)吗?

gets called. Is this a limitation on a number of threads or a built-in CLGeocoder limitation? Could it be that I'm not cleaning up geocoders properly and need some sort of an autorelease statement(ARC)?

- (void)geocodeArray:(NSMutableArray *)数组
{

-(void)geocodeArray:(NSMutableArray*)array {

    NSMutableDictionary* htc = nil;
    objectsToGeocode = array.count;

    NSDictionary *htcDictionary =nil;
     for (int i = 0; i<array.count;i++) {
         htcDictionary = [array objectAtIndex:i];

        //create an updated dictionary that would hold the reverse geocoding location
        htc = [[NSMutableDictionary alloc] initWithDictionary:htcDictionary];
        NSLog(@"geocoding: %@",[htc objectForKey:kAddressKey]);

        CLGeocoder* geoCoder = [[CLGeocoder alloc] init];
        [geoCoder geocodeAddressString:[htc objectForKey:kAddressKey] completionHandler:^(NSArray *placemarks, NSError *error) {

            if(placemarks.count>0)
            {
                NSLog(@"Found placemarks for %@",[htc objectForKey:kAddressKey]);
                CLPlacemark* placemark =  [placemarks objectAtIndex:0];
                MyLocation *annotation = [[MyLocation alloc]
                                          initWithName:[htcDictionary objectForKey:kNameKey]
                                          address:[htcDictionary objectForKey:kAddressKey]
                                          coordinate:placemark.location.coordinate] ;
                annotation.faxNumber = [htc objectForKey:kFaxKey];
                annotation.phoneNumber = [htc objectForKey:kPhoneKey];
                annotation.website = [htc objectForKey:kWebsiteKey];
                annotation.type = [htc objectForKey:kFacilityTypeKey];
                [_mapView addAnnotation:annotation];  


                double placemarkToUserDistance = [self._mapView.userLocation.location distanceFromLocation:placemark.location] ;
                //convert distance to miles
                placemarkToUserDistance =placemarkToUserDistance/ 1000/ kKilometersPerMile;

                [htc setObject:[NSNumber numberWithDouble:placemarkToUserDistance] forKey:kDistanceToUserKey];
                [htc setObject:[NSNumber numberWithDouble:placemark.location.coordinate.latitude] forKey:kLatitudeKey];
                 [htc setObject:[NSNumber numberWithDouble:placemark.location.coordinate.longitude] forKey:kLongitudeKey];
                NSAssert([htc objectForKey:kLatitudeKey]!=nil,@"kLatitudeKey is not saved!");
                NSAssert([htc objectForKey:kLongitudeKey]!=nil,@"kLongitudeKey is not saved!");

            }else {
                NSLog(@"Address not recognized: *%@*",[htc objectForKey:kAddressKey]);
            }


            [self.dataSource addObject:htc];

            if(++geocodingCount >=objectsToGeocode){
                NSLog(@"%@",self.dataSource);
                    [self saveGeocoding];

            }

        } ];


        //        [temp addObject:htcDictionary];
    }

}

测试这是否是线程问题,我创建了这个方法,它将我的大数据集拆分为5个数组,并尝试将它们分块进行地理编码。我注意到第一个请求通过,第二个请求通过。但是一旦达到(~50)的幻数,地理编码就会停止。

To test if this is a threading issue, I created this method, which splits my large dataset into 5 arrays, and attempts to geocode them in chunks. I noticed that the first request passes, as well as a part of a second one. But once the magic number of (~50) is reached, the geocoding stops.

有关可能发生的事情的任何想法? 这是Apple对地理编码操作数量的限制吗?我是否应该增加请求之间的延迟或尝试分别运行应用程序5并手动拼凑结果?

Any ideas of what may be happening? Is this an Apple imposed limit on the number of geocoding operations? Should I increase the delay between requests or try to run the app 5 separate times and piece together the results by hand?

-(void)geocodeDatasource
{

        //I'm trying to build a file with coordinates of addresses and include it with the app
        geocodingCount = 0;
        self.dataSource = [[NSMutableArray alloc] initWithCapacity:self.arrayForGeocodingInitialJSON.count+5];
        haveToEmailInitialResults = YES;


    //attempt to geocode in batches

     float numberOfArrays = 5.0;
    NSMutableArray* array1 = [[NSMutableArray alloc] initWithCapacity:arrayForGeocodingInitialJSON.count/numberOfArrays];
    NSMutableArray* array2 = [[NSMutableArray alloc] initWithCapacity:arrayForGeocodingInitialJSON.count/numberOfArrays];
    NSMutableArray* array3 = [[NSMutableArray alloc] initWithCapacity:arrayForGeocodingInitialJSON.count/numberOfArrays];
    NSMutableArray* array4 = [[NSMutableArray alloc] initWithCapacity:arrayForGeocodingInitialJSON.count/numberOfArrays];
    NSMutableArray* array5 = [[NSMutableArray alloc] initWithCapacity:arrayForGeocodingInitialJSON.count/numberOfArrays];

    for(int i = 0 ;i<arrayForGeocodingInitialJSON.count;i++)
    {
        id object = [arrayForGeocodingInitialJSON objectAtIndex:i];
        if(i<arrayForGeocodingInitialJSON.count*(1/numberOfArrays))
        {
            [array1 addObject:object];
        }else if(i>=arrayForGeocodingInitialJSON.count/numberOfArrays && i<arrayForGeocodingInitialJSON.count*(2/numberOfArrays))
        {
            [array2 addObject:object];
        }else if(i>=arrayForGeocodingInitialJSON.count*(2/numberOfArrays) && i<arrayForGeocodingInitialJSON.count*(3/numberOfArrays))
        {
            [array3 addObject:object];
        }else if(i>=arrayForGeocodingInitialJSON.count*(3/numberOfArrays) && i<arrayForGeocodingInitialJSON.count*(4/numberOfArrays))
        {
            [array4 addObject:object];
        }else if(i>=arrayForGeocodingInitialJSON.count*(4/numberOfArrays) && i<arrayForGeocodingInitialJSON.count)
        {
            [array5 addObject:object];
        }



    }

    //simple delays eliminate the need for extra variables and notifications
        [self geocodeArray:array2];

        [self performSelector:@selector(geocodeArray:) withObject:array1 afterDelay:15];
        [self performSelector:@selector(geocodeArray:) withObject:array3 afterDelay:30];
        [self performSelector:@selector(geocodeArray:) withObject:array4 afterDelay:45];
        [self performSelector:@selector(geocodeArray:) withObject:array5 afterDelay:45];
}

谢谢!

推荐答案

您无法立即对大型集进行地理编码。 iOS限制了你。我已经看到iOS一次限制你50个地理编码,时间因素是未知的。

You can't immediately geocode large sets. iOS throttles you. I have seen that iOS limits you to 50 geocodes at a time, with the "time" factor being an unknown.

我遇到了类似的问题,但是我我只需要按时间顺序向用户提供地理编码数据,我将所有地理编码排队。

I've had a similar problem, but as I needed only to present the geocoding data in a sequence to the user that takes time, I queued all my geocodings.

实际上,我对一个25的地块进行了地理编码 - 显示结果在每个之间以大约半秒的间隔向用户1发送。当我剩下少于4个显示时,我将对下一个25进行地理编码。这将持续到所有地理编码(或者在我的情况下,无限期)。

Effectively, I geocode a chunk of 25 - display the results to the user 1 at a time at about an interval of a half second between each. When I have fewer than 4 left to display, I will geocode the next 25. This continues until everything is geocoded (or in my case, indefinitely).

如果你需要要让所有内容一次完成地理编码,您需要将每个块之间的延迟链接在一起,并显示某种忙碌指示,直到完成为止。对于大型的地理编码,可能需要一段时间。

If you need to have everything geocoded at once, you'll need to chain your geocodings together with delays between each chunk and show some sort of busy indicator until you are done. Which could be some time with large sets of geocodings.

这篇关于iPhone iOS5 CLGeocoder如何对大(200)个地址进行地理编码?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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