将 javascript 计算样式从一个元素设置/复制到另一个元素 [英] Set / Copy javascript computed style from one element to another

问题描述

所以我试图复制适用于一个元素的所有样式(类/id/tagName/属性等).到目前为止，我发现我可以复制元素的计算样式，只有一个问题...可以将其应用于外部元素；/

So I am trieing to copy all the style that apply on one element ( class / id / tagName / attribute etc. ). So far I found out that I can copy the computed style of an element, Just one problem ... couldend apply it on outher element ;/

或者用不同的方式复制所有的样式.

or diffrend way to copy all the style.

(据我所知:/)http://jsfiddle.net/8KdJd/2/

   //queriks mode + minor changes to retrive the computed style
function getCS(el)
{
    if (el.currentStyle)
        var y = el.currentStyle;
    else if (window.getComputedStyle)
        var y = document.defaultView.getComputedStyle(el,null);
    return y;
}
function setCS(el,cs)
{
    if (el.currentStyle)
    {

        el.currentStyle = cs;
        el.style = cs;
    }
    else if (window.getComputedStyle)
    {el.style = cs 
    }

}


var myLink = document.getElementById('myLink');
var anotherLink = document.getElementById('anotherLink');

var CS_myLink = getCS(myLink);
setCS(anotherLink,CS_myLink);

推荐答案

更新:正如@icl7126 所建议的，这里有一个几乎相同用法的较短版本.值得记住的是，如果没有预编译，此代码将无法在大多数/较旧的浏览器上运行.

Update: As @icl7126 suggested, here is a shorter version for practically the same usage. good thing to remember that this code would not run on most/older browser if not pre-compiled.

原件(ES 2017):

Original (ES 2017):

function copyNodeStyle(sourceNode, targetNode) {
  const computedStyle = window.getComputedStyle(sourceNode);
  Array.from(computedStyle).forEach(key => targetNode.style.setProperty(key, computedStyle.getPropertyValue(key), computedStyle.getPropertyPriority(key)))
}

预编译(ES 5):

function copyNodeStyle(sourceNode, targetNode) {
  var computedStyle = window.getComputedStyle(sourceNode);
  Array.from(computedStyle).forEach(function (key) {
    return targetNode.style.setProperty(key, computedStyle.getPropertyValue(key), computedStyle.getPropertyPriority(key));
  });
}

#

13 年 11 月发布的原始答案.当时不支持 CSS 变量.(2014 年 7 月首次在 Firefox 上推出)

就是这样！我明白了:)

Thats it! I got it :)

我看到很多人都在看这个问题，所以下面是更详细和更干净的代码.

Iv'e seen that lots of people view this question, So below is more detailed and clean code.

var copyComputedStyle = function(from,to){
    var computed_style_object = false;
    //trying to figure out which style object we need to use depense on the browser support
    //so we try until we have one
    computed_style_object = from.currentStyle || document.defaultView.getComputedStyle(from,null);

    //if the browser dose not support both methods we will return null
    if(!computed_style_object) return null;

        var stylePropertyValid = function(name,value){
                    //checking that the value is not a undefined
            return typeof value !== 'undefined' &&
                    //checking that the value is not a object
                    typeof value !== 'object' &&
                    //checking that the value is not a function
                    typeof value !== 'function' &&
                    //checking that we dosent have empty string
                    value.length > 0 &&
                    //checking that the property is not int index ( happens on some browser
                    value != parseInt(value)

        };

    //we iterating the computed style object and compy the style props and the values 
    for(property in computed_style_object)
    {
        //checking if the property and value we get are valid sinse browser have different implementations
            if(stylePropertyValid(property,computed_style_object[property]))
            {
                //applying the style property to the target element
                    to.style[property] = computed_style_object[property];

            }   
    }   

};

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