查找距离点最近的坐标 [英] Finding the closest coordinates to a point

问题描述

我有城市坐标：(52.2319581, 21.0067249)和Python字典，上面提到的城市周围有城市。如何从给定的坐标中获取最近的3个城市：

({'Brwinów': (52.133333, 20.716667), 'Warszawa Bielany': (52.283333, 20.966667), 'Legionowo': (52.4, 20.966667), 'Warszawa-Okęcie': (52.16039, 20.961674), 'Warszawa': (52.280957, 20.961348), 'Belsk Duży': (51.833333, 20.8)}, {})

感谢您的帮助。

推荐答案

不带任何外部库

from math import acos, cos, sin

def gc_distance(first_point, second_point):
    return acos(sin(first_point[1]) * sin(second_point[1]) + cos(first_point[1]) * cos(second_point[1]) * cos(first_point[0] - second_point[0]))

def three_closest(city, cities):
    cities_distances = { key: gc_distance(city, value) for key, value in cities.items()}
    return [k for k, v in sorted(cities_distances.items(), key=lambda item: item[1])][:3]

样本测试：

>>> city = (52.2319581, 21.0067249)
>>> cities = {'Brwinów': (52.133333, 20.716667), 'Warszawa Bielany': (52.283333, 20.966667), 'Legionowo': (52.4, 20.966667), 'Warszawa-Okęcie': (52.16039, 20.961674), 'Warszawa': (52.280957, 20.961348), 'Belsk Duży': (51.833333, 20.8)}
>>> three_closest(city, cities)
['Warszawa Bielany', 'Warszawa', 'Warszawa-Okęcie']

如果要返回键和值，请执行以下操作：

for result in three_closest(city, cities):
    print(result + " : " + str(cities[result]))

获取：

Warszawa Bielany : (52.283333, 20.966667)
Warszawa : (52.280957, 20.961348)
Warszawa-Okęcie : (52.16039, 20.961674)

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