不确定如何与MOV(A,B,C),D工作 [英] Unsure how to work with mov (a,b,c),d
问题描述
什么是MOV在这里做什么?
MOV(%EBX,EAX%,4),EAX%
我见过MOV用于从一个功能到另一个转移的价值,但我不知道如何处理这种情况。
段:排量(基址寄存器,偏移寄存器,标量倍增)
[在AT& T公司语法相当于]段:基址寄存器+位移+偏移寄存器*英特尔语法标量倍增]
。 (源)
块引用>所以
MOV(%EBX,%EAX,4),%EAX
等同于MOV EAX,[EBX + EAX * 4]
。也就是说,形成由地址EBX + EAX * 4
,并从该地址的双加载到EAX
。What is mov doing here?
mov(%ebx,%eax,4),%eax
I've seen mov used to transfer a value from one function to another, but I'm not sure how to handle this situation.
解决方案
segment:displacement(base register, offset register, scalar multiplier)
[in AT&T syntax is equivalent to]segment:[base register + displacement + offset register * scalar multiplier]
in Intel syntax. (source)So
mov(%ebx,%eax,4),%eax
is equivalent tomov eax, [ebx + eax*4]
. That is, form an address byebx + eax*4
and load a doubleword from that address intoeax
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