如何扭转在汇编语言的字符串？ [英] How to reverse a string in assembly language?

问题描述

我刚开始学习汇编语言的，我要打印的Hello World以相反的顺序，这意味着dlrow东海生日贺。问题是我得到只有第一个字母为输出，令仍然一样没有变化在所有！作为一个新手，很多东西是未知的，我和我在做很多错误，我无法确定他们由于缺乏knowledge.So的适当解释任何回答将是AP preciated！这里是我的code：

 名为喜;有谁能够解释什么用的呢？组织100HJMP启动;跳过数据声明味精DB1Hello，世界！，0;最后一个字符
MSG1 DB1MOV SI，13;字符串的lenght
开始：MOV AL，味精[SI]
DEC SIMOV啊，0EH
INT 10H
MOV BL，MSG1CMP味精[SI]，BL;比较，以获得弦的端部
JE停止JMP启动停止：
MOV啊，0
INT 16H;等待任何关键....
RET;返回到操作系统。
 

我得到的输出只有1，这是首个字母，但我希望得到相反的顺序整个字符串

解决方案

  JMP启动;跳过数据declaratio
...
MOV SI，13;字符串的lenght
开始：
 

现在的问题是 - 你没有初始化寄存器 SI

您需要使用这样的：

  JMP初始化;跳过数据declaratio
...
在里面：
MOV SI，13;字符串的lenght
开始：
 

I have just started to learn assembly language and i am trying to print "hello world" in reverse order that means "dlrow olleh".the problem is i am getting only 1st letter as output and the order is still same no change at all!As a newbie many thing is unknown to me and i am doing lots of mistakes and i am unable to identify them due to lack of knowledge.So any answer with proper explanation will be appreciated!Here is my code:

name "hi" ; can anybody explain what is the use of this?

org 100h

jmp start       ; jump over data declaration

msg    db      "1Hello, World!",0;last character           
msg1   db      "1"

Mov   SI,13;lenght of the string
start: 

Mov  AL,msg[SI]
DEC SI 

Mov  ah ,0eh
int 10h   
mov BL,msg1

CMP msg[SI],BL;comparing to get the end of the string
je stop

jmp start                     

stop:
mov     ah, 0 
int     16h      ; wait for any key....
ret ; return to operating system.

i am getting output only "1" which is the first letter,but i expected to get the whole string in reverse order

解决方案

jmp start       ; jump over data declaratio
...
Mov   SI,13;lenght of the string
start: 

here is the problem - you're not initializing register si

you need to use something like:

jmp init       ; jump over data declaratio
...
init:
Mov   SI,13;lenght of the string
start: 

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