Expect脚本返回值 [英] Expect Script Return Value

问题描述

我包括简单的bash脚本（我知道我可以只是写一个纯粹的Expect脚本，但我想获得它从庆典中工作）。

中期待的命令

该脚本如下：

 ＃！/斌/庆典输出= $（预计-c'
产卵SSH [e-mail]
预计密码
发送狗\\ R
'）
 

一旦ssh'ing上面的地址，它会返回形式的东西 mihail911的密码：上的提示，所以我觉得我的期望线是有效的。当我运行此我的脚本不打印任何东西。它甚至没有显示密码：提示符。一般情况下，即使我手动提供的密码不正确，我将获得密码不正确型反应迅速。为什么没有打印，我怎么能得到我的脚本正确执行？我已经使用 -d 标记尝试调试，这似乎表明，至少在第一期望提示正在正确匹配。

另外，我应该期望在输出变量什么样的价值观？当我回声这个变量，它只是打印第一个脚本的期望部分，然后的第一个命令 mihail911的密码：。请问这是什么它应该是打印？

感谢您的帮助！

解决方案

 ＃！/斌/庆典
输出= $（预计-c'
        ＃共进晚餐preSS通过衍生过程中产生的输出的任何其他形式
        LOG_USER 0
        产卵SSH [e-mail]
        ＃为了配合一些常用的提示。更新根据您的需要。
        ＃要匹配字面美元，这是转义反斜杠
        设置提示＃|＆GT; | \\\\ $
        预计{
                EOF {看跌期权连接主机拒绝;退出0}
                超时{看跌期权无法访问主机出口0;}
                密码：
        }
        发送根\\ r
        预计{
                超时{看跌期权无法访问主机出口0;}
                -re $提示符
        }
        发送日期\\ R
        ＃匹配唯独日期CMD输出
        预计{
                超时{看跌期权无法访问主机退出0}
                -re\\ n（\\ [^ \\ r] *）\\ r
        }
        send_user$ expect_out（1，字符串）\\ n
        1号出口
'）
回声期待的返回值：$？;从返回＃打印值'期待'
回声期望输出：$ OUTPUT
 

输出：

 迪内希@ MYPC：〜/计算器$ ./Meric
预期的返回值：1
期望输出：星期三09月02日九时35分14秒2015年IST
迪内希@ MYPC：〜/计算器$
 

I'm including simple Expect commands within a bash script (I know I could be just writing a pure Expect script but I would like to get it to work from within bash).

The script is below:

#!/bin/bash

OUTPUT=$(expect -c '
spawn ssh [e-mail]
expect "password:"
send "dog\r"
')

Upon ssh'ing to the above address, it will return something of the form mihail911's password: on the prompt so I think my expect line is valid. When I run this my script does not print anything. It does not even show the password: prompt. In general, even if I manually provide an incorrect password, I will receive a Incorrect password-type response prompt. Why is nothing printing and how can I get my script to execute properly? I have tried debugging by using the -d flag and it seems to show that at least the first expect prompt is being matched properly.

In addition, what values should I expect in the OUTPUT variable? When I echo this variable, it simply prints the first the first command of the expect portion of the script and then mihail911's password:. Is this what it's supposed to be printing?

Thanks for the help!

解决方案

#!/bin/bash
OUTPUT=$(expect -c '
        # To suppress any other form of output generated by spawned process
        log_user 0
        spawn ssh [e-mail]
        # To match some common prompts. Update it as per your needs.
        # To match literal dollar, it is escaped with backslash
        set prompt "#|>|\\$"
        expect {
                eof     {puts "Connection rejected by the host"; exit 0}
                timeout {puts "Unable to access the host"; exit 0;}
                "password:"
        }
        send "root\r"
        expect {
                timeout {puts "Unable to access the host"; exit 0;}
                -re $prompt
        }
        send "date\r"
        # Matching only the date cmd output alone
        expect {
                timeout { puts "Unable to access the host";exit 0}
                -re "\n(\[^\r]*)\r"
        }
        send_user "$expect_out(1,string)\n"
        exit 1
')
echo "Expect's return value : $?"; # Printing value returned from 'Expect'
echo "Expect Output : $OUTPUT"

Output :

dinesh@MyPC:~/stackoverflow$ ./Meric 
Expect's return value : 1
Expect Output : Wed Sep  2 09:35:14 IST 2015
dinesh@MyPC:~/stackoverflow$ 

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