从蟒蛇内运行bash脚本 [英] Running bash script from within python

问题描述

我有以下code的一个问题：

I have a problem with the following code:

callBash.py：

import subprocess
print "start"
subprocess.call("sleep.sh")
print "end"

sleep.sh：

sleep 10

我想10秒后要被打印的结束。 （我知道这是一个愚蠢的例子，我可以简单地蟒蛇内睡觉，但这个简单的sleep.sh文件只是作为测试）

I want the "end" to be printed after 10s. (I know that this is a dumb example, I could simply sleep within python, but this simple sleep.sh file was just as a test)

推荐答案

制作sleep.sh可执行文件并加入壳= TRUE 参数列表（如建议在previous答案）工程确定。根据不同的搜索路径，您可能还需要添加 ./ 或其他一些合适的路径。 （也就是说，变化sleep.sh到./ sleep.sh）

Making sleep.sh executable and adding shell=True to the parameter list (as suggested in previous answers) works ok. Depending on the search path, you may also need to add ./ or some other appropriate path. (Ie, change "sleep.sh" to "./sleep.sh".)

的 SHELL =不需要真参数（POSIX的系统如Linux下）如果bash脚本的第一行是一个shell的路径;例如，＃！/斌/庆典。

The shell=True parameter is not needed (under a Posix system like Linux) if the first line of the bash script is a path to a shell; for example, #!/bin/bash.

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