从运行Python中的bash脚本 [英] Running a bash script from Python

问题描述

我需要运行在Python bash脚本。我得到它的工作方式如下：

I need to run a bash script from Python. I got it to work as follows:

import os
os.system("xterm -hold -e scipt.sh")

这不正是我在做什么，但pretty太多的想法。这工作正常，新的终端窗口打开，我拿着它进行调试，但我的问题是我需要的python脚本继续运行，即使没有完成。什么办法可以做到这一点？

That isn't exactly what I am doing but pretty much the idea. That works fine, a new terminal window opens and I hold it for debugging purposes, but my problem is I need the python script to keep running even if that isn't finished. Any way I can do this?

推荐答案

我推荐你使用子模块：的文档

I recommend you use subprocess module: docs

您可以

import subprocess

cmd = "xterm -hold -e scipt.sh"
# no block, it start a sub process.
p = subprocess.Popen(cmd , shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

# and you can block util the cmd execute finish
p.wait()
# or stdout, stderr = p.communicate()

有关更多信息，请阅读文档，。）

For more info, read the docs,:).

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