bash脚本 - 不能得到循环工作 [英] bash script - can't get for loop working
问题描述
背景资料：
我试图按照张贴在这里的例子： HTTP：// WWW。 cyberciti.biz/faq/bash-for-loop/
我想循环中使用所谓的我控制变量9倍。
I'm trying to follow the example posted here: http://www.cyberciti.biz/faq/bash-for-loop/ I would like loop 9 times using a control variable called "i".
问题说明
我的code是这样的：
My code looks like this:
for i in {0..8..1}
do
echo "i is $i"
tmpdate=$(date -d "$i days" "+%b %d")
echo $tmpdate
done
当我运行这个code，调试打印告诉我：
When I run this code, the debug prints show me:
"i is {0..8..1}"
，而不是为0和8之间的值
instead of being a value between 0 and 8.
什么，我经过这么远：
我试图来检查我的版本的bash，以确保它支持这种类型的语法。我运行的版本4,2,25（1）
I've tried to check my version of bash to make sure it supports this type of syntax. I'm running version 4,2,25(1)
我用C一样，你对做语法也试过（; I＆LT; I = 0 = 8;我+ +），但也不起作用。
I also tried using C like syntax where you do for (i=0;i<=8;i++) but that doesn't work either.
任何建议将是AP preciated。
Any suggestions would be appreciated.
感谢。
修改1
我也试过以下code：
I've also tried the following code:
for i in {0..8};
do
echo "i is $i"
tmpdate=$(date -d "$i days" "+%b %d")
echo $tmpdate
done
和...
for i in {0..8}
do
echo "i is $i"
tmpdate=$(date -d "$i days" "+%b %d")
echo $tmpdate
done
他们都失败，出现相同的结果。
They all fail with the same results.
我也试过：
#!/bin/bash
for ((i=0;i<9;i++));
do
echo "i is $i"
tmpdate=$(date -d "$i days" "+%b %d")
echo $tmpdate
done
这给我的错误：
test.sh：4：test.sh：语法错误：坏的循环变量
test.sh: 4: test.sh: Syntax error: Bad for loop variable
仅供参考。我在Ubuntu上运行12
FYI. I'm running on ubuntu 12
编辑2
好吧......所以，我认为Weberick通风报信我送行的问题...
要执行脚本，我跑的sh test.sh
当在code我有它定义为一个bash脚本！我的坏！
Ok... so i think Weberick tipped me off to the issue... To execute the script, I was running "sh test.sh" when in the code I had defined it as a BASH script! My bad!
但这里的东西。最后，我需要在这两个bash和sh的工作。
所以现在我得谨慎小心，以确保我调用脚本以正确的方式......我已经注意到了以下结果：
But here's the thing. Ultimately, I need it to work in both bash and sh. so now that I'm being careful to make sure that I invoke the script the right way... I've noticed the following results:
- 当定义为一个bash脚本和我执行使用bash，C风格的版本的作品！
-
当定义为一个sh脚本，我使用执行SH，C风格的版本失败
- when defined as a bash script and i execute using bash, the C-style version works!
when defined as an sh script and i execute using sh, the C-style version fails
我@ devbox：〜/ tmp / test目录$ SH test.sh
test.sh：5：test.sh：语法错误：坏的循环变量
me@devbox:~/tmp/test$ sh test.sh test.sh: 5: test.sh: Syntax error: Bad for loop variable
当定义为一个sh脚本，我使用执行的SH非空调风格版（又名为我{N ..x}），我得到了我是{} 0..8输出。
when defined as an sh script and i execute using sh the NON c style version ( aka for i in {n ..x}), I get the "i is {0..8}" output.
PS。的，不有所作为，如果你对下一行做...只是供参考。
PS. The ";" doesn't make a difference if you have the do on the next line...just FYI.
推荐答案
Ubuntu的默认外壳是破折号，不承认无论是bash化的（括号扩展，C风格的for循环），你试过。尝试使用运行脚本庆典明确：
Ubuntu's default shell is dash, which doesn't recognise either of the bashisms (brace expansion, C-style for loop) you tried. Try running your script using bash explicitly:
bash myscript.sh
或由家当设置为＃！/斌/庆典。确保不要运行该脚本 SH myscript.sh 。
or by setting the shebang to #!/bin/bash. Make sure NOT to run the script with sh myscript.sh.
如果您使用破折号应该工作 SEQ ：
dash should work if you use seq:
for i in $(seq 0 1 8); do
echo "$i"
done
只是 {0..8} 应庆典工作，默认增量为1。如果你想使用C风格的for循环庆典：
Just {0..8} should work in bash, the default increment is 1. If you want to use a C-style for loop in bash:
for ((i=0;i<9;i++)); do
echo "$i"
done
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