AWK不bash脚本工作 [英] AWK doesn't work in Bash Script

问题描述

我有一个脚本以下AWK语句：

I have the following AWK statement in a script:

grep -E $city $DATFILE | awk -F "[\t]+" '($3 >= $minbed) && ($4 >= $minsqft) && ($5 <= $maxprice) && ($6 <= $maxweeks)' $DATFILE | sort -nk5 | less

当我运行该脚本，输出是空白。但是，如果我运行以下命令：

When I run the script, the output is blank. However, if I run the following:

grep -E Toronto listing.dat | awk -F "[\t]+" '($3 >= 2) && ($4 >= 500) && ($5 <= 900000) && ($6 <= 10)' listing.dat | sort -nk4 | less

据产出预期。

我不知道为什么发生这种情况，我甚至已经取代了脚本回声出变量awk的语句，以确保他们正确传递，他们是。

I have no idea why this is happening, and I have even replaced the awk statement in the script to echo out the variables to make sure they're passing correctly and they are.

下面是脚本迄今：

    #!/bin/bash

    DATFILE=listing.dat

    if [ -f ${DATFILE} ];
    then

            echo -n "Are you looking into anywhere in the GTA, or a specific city?: "
            read uinput

            if [ $uinput == "anywhere" ];
            then
                    echo "You have chosen anywhere"
            elif [ $uinput == "specific" ];
            then
                    echo -n "Which city?: "
                    read city

                    echo -n "Minimum Number of Bedrooms: "
                    read minbed

                    echo -n "Minimum Square Footage (500, 600, etc): "
                    read minsqft

                    echo -n "Maximum Price: "
                    read maxprice

                    echo -n "Maximum Weeks On Market: "
                    read maxweeks

                    echo -n "Sort by (price, sqrft, weeks): "
                    read sortby

                    if [ $sortby == "price" ];
                    then
                            echo -n "Sort by (asc, desc): "
                            read ascdesc
                            if [ $ascdesc == "asc" ];
                            then
                                    grep -E $city $DATFILE | awk -F "[\t]+" '($3 >= $minbed) && ($4 >= $minsqft) && ($5 <= $maxprice) && ($6 <= $maxweeks)' $DATFILE | sort -nk5 | less
                        elif [ $ascdesc == "desc" ];
                        then
                                grep -E $city $DATFILE | awk -F "[\t]+" '($3 >= $minbed) && ($4 >= $minsqft) && ($5 <= $maxprice) && ($6 <= $maxweeks)' $DATFILE | sort -rnk5 | less
                        fi
                fi

        fi

else
        echo "${DATFILE} Not found!"
fi

您可以请帮助？

感谢

推荐答案

如果新的* nix的工具，你可以看到使用人utility_name的基本文档;从'awk的'（AWK人）的手册页：

If new to any *nix utility, you can see basic docs using 'man utility_name'; from the man page for 'awk' (man awk):

-v VAR = VAL结果
        分配值VAL到变量var，程序的执行开始之前。这样的变量值可用来BEGIN块
  一个AWK程序。

-v var=val
Assign the value val to the variable var, before execution of the program begins. Such variable values are available to the BEGIN block of an AWK program.

有其他方法可以做到这一点，但在之后的文档code将改为类似：

There are other ways to do this, but following the docs your code would be changed to something like:

awk -F "[\t]+" \  
  -v MINBED=$minbed -v MINSQFT=$minsqft -v MAXPRICE=$maxprice -v MAXWEEKS=$maxweeks \
  '($3 >= MINBED) && ($4 >= MINSQFT) && ($5 <= MAXPRICE) && ($6 <= MAXWEEKS)'  

这篇关于AWK不bash脚本工作的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！