正则表达式中的if语句匹配空格的字符串（用引号？） [英] Regex match a string with spaces (use quotes?) in an if statement

问题描述

会怎么做一个正则表达式匹配如下，但周围的报价显示的（^本）作为在现实世界这将是可以有空格在它的字符串。

How would I do a regex match as shown below but with quotes around the ("^This") as in the real world "This" will be a string that can have spaces in it.

#!/bin/bash

text="This is just a test string"
if [[ "$text" =~ ^This ]]; then
 echo "matched"

else
 echo "not matched"
fi

我想要做这样的事情。

I want to do something like

    if [[ "$text" =~ "^This is" ]]; then

但是，这并不匹配。

but this doesn't match.

推荐答案

您可以使用 \\ 之前的空格。

You can use \ before spaces.

#!/bin/bash

text="This is just a test string"
if [[ "$text" =~ ^This\ is\ just ]]; then
  echo "matched"
else
  echo "not matched"
fi

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