布尔值的Objective-C的dealloc [英] Objective-c dealloc of boolean value

问题描述

我将如何的dealloc 一个布尔值？

Deallocing它下面这种方式给了我一个警告：不兼容的指向整数转换​​分配给从布尔（又名符号字符'）'无效*'

Deallocing it this way below gives me a warning: Incompatible pointer to integer conversion assigning to 'BOOL' (aka 'signed char') from 'void *'

- (void)dealloc {
    self.booleanVar = nil;
    [super dealloc];
}

也许我应该澄清，这是从NSObject的继承了一个简单的类。

Perhaps I should clarify, this is from a simple class inherited from NSObject.

我使用在可可触摸类看self.var =零格局。比方说，如果这是一个NSString *代替，我应该使用self.var =零，或在的dealloc 法[VAR发布]我有点困惑在这里。

I'm using the self.var = nil pattern that you see in Cocoa Touch classes. Let's say if it was an NSString* instead should I use self.var = nil or [var release] in the deallocmethod? I'm a little confused here.

推荐答案

您不必这样做。它的不可以的对象。这也解释了警告，因为你要分配一个零指针（这是一个对象的基本NULL）向非对象。

You don't need to do it. It is not an object. This also explains the warning, as you're trying to assign a nil pointer (that's a NULL for objects basically) to a non-object.

关于你的第二个问题，是的。你可以把原始变量作为是对象的一部分，所以当它被释放的增值经销商将不再存在。

Regarding your second question, yes. You can think of primitive variables as being part of the object, so when it's deallocated the vars will not exist anymore.

但是，当你有一个的NSString * 中的对象，它只是一个指向另一个对象。如果你的dealloc前，指针将被删除，而不是的NSString 。没有人会指向它，它是一种失去了在空气中，占用的内存。因此，删除指针之前，如果你不需要对象了，你把它释放的消息。这是在dealloc方法做的，因为它叫删除和对象，因此也删除已经没有用了其他所有对象的好地方。

But when you have a NSString * in an object, it's just a pointer to another object. If you dealloc the former, the pointer will be deleted, not the NSString. No one might point to it, it's kind of lost in the air, occupying memory. So, before deleting the pointer, if you won't need the object anymore, you send it a release message. That's done in the dealloc method, since it's called to "delete" and object and thus is a good place to delete also every other object that has no use anymore.

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