转换到的int64_t TIME_DURATION [英] Convert int64_t to time_duration
问题描述
我想通过网络为的boost ::的int64_t
转移的boost ::了posix_time ::分组时间>。据打开的boost ::了posix_time一种方法::分组时间到一个__int64 ,我可以很容易地定义自己的的划时代的,只有从参考时间为64位整数传送
TIME_DURATION
。但如何转换回一个分组时间
?
I would like to transfer a boost::posix_time::ptime
over the network as a boost::int64_t
. According to A way to turn boost::posix_time::ptime into an __int64, I can easily define my own epoch and only transfer the time_duration
from that reference epoch as a 64 bits integer. But how to convert back to a ptime
?
#include <iostream>
#include <cassert>
#include <boost/date_time/posix_time/posix_time.hpp>
#include <boost/date_time/gregorian/greg_month.hpp>
using namespace std;
using boost::posix_time::ptime;
using boost::posix_time::time_duration;
using boost::gregorian::date;
int main(int argc, char ** argv){
ptime t = boost::posix_time::microsec_clock::local_time();
// convert to int64_t
ptime myEpoch(date(1970,boost::gregorian::Jan,1));
time_duration myTimeFromEpoch = t - myEpoch;
boost::int64_t myTimeAsInt = myTimeFromEpoch.ticks();
// convert back to ptime
ptime test = myEpoch + time_duration(myTimeAsInt);
assert(test == t);
return 0;
}
这是不是因为 TIME_DURATION
构造采取滴答计数的说法是私人的工作。我也有兴趣在任何其他方式传送简单的分组时间
过简单的数据类型。
This is not working since the time_duration
constructor taking a tick count as argument is private. I am also interested in any other way to simply transfer that ptime
over simple data types.
推荐答案
是毫秒级工作液:
int main(int argc, char ** argv){
ptime t = boost::posix_time::microsec_clock::local_time();
// convert to int64_t
ptime myEpoch(date(1970,boost::gregorian::Jan,1));
time_duration myTimeFromEpoch = t - myEpoch;
boost::int64_t myTimeAsInt = myTimeFromEpoch.total_milliseconds();
// convert back to ptime
ptime test = myEpoch + boost::posix_time::milliseconds(myTimeAsInt);
cout << test << endl;
cout << t << endl;
time_duration diff = test - t;
assert(diff.total_milliseconds()==0);
return 0;
}
由于12a6上。
Thanks 12a6.
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