铸造一架C结构到另一个 [英] Casting one C structure into another

问题描述

我有两个相同（但命名不同）C的结构：

I have two identical (but differently named) C structures:

typedef struct {
      double x;
      double y;
      double z;
} CMAcceleration;


typedef struct {
    double x;
    double y;
    double z;   
} Vector3d;

现在我想将CMAcceleration变量分配给一个变​​量的Vector3D（复制整个结构）。我怎样才能做到这一点？

Now I want to assign a CMAcceleration variable to a Vector3d variable (copying the whole struct). How can I do this?

我尝试以下，但获得这些编译器错误：

I tried the following but get these compiler errors:

vector = acceleration;           // "incompatible type"
vector = (Vector3d)acceleration; // "conversion to non-scalar type requested"

当然，我可以诉诸单独设置所有成员：

Of course I can resort to set all members individually:

vector.x = acceleration.x;
vector.y = acceleration.y;
vector.z = acceleration.z;

但似乎相当不方便。

but that seems rather inconvenient.

什么是最好的解决方案？

What's the best solution?

推荐答案

这（从包成一个功能除外）是你唯一的解决办法：

That's your only solution (apart from wrapping it into a function):

vector.x = acceleration.x;
vector.y = acceleration.y;
vector.z = acceleration.z;

其实你可以施放它，像这样（使用指针）

You could actually cast it, like this (using pointers)

Vector3d *vector = (Vector3d*) &acceleration;

但是这是不是在规格，因此行为取决于编译器，运行和大型绿地的怪物。

but this is not in the specs and therefore the behaviour depends on the compiler, runtime and the big green space monster.

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