c - 从中​​读取标准输入的字符被键入 [英] C - Reading from stdin as characters are typed

问题描述

我如何用字符填写一个80字符缓冲区，因为他们正在进入或直到回车键为pressed，或缓冲区已满，以先到为准。

How do I fill an 80-character buffer with characters as they are being entered or until the carriage return key is pressed, or the buffer is full, whichever occurs first.

我已经研究过很多不同的方式，但进入已被pressed则输入字符*得到80切断。

I've looked into a lot of different ways, but enter has to be pressed then the input char* gets cut off at 80..

感谢。

推荐答案

如果你真的想要的人物，因为他们输入，你不能用C IO。你必须做它的UNIX方式。 （或窗口方式）

If you really want the characters "as they are entered", you cannot use C io. You have to do it the unix way. (or windows way)

#include <stdio.h>
#include <unistd.h>
#include <termios.h>
int main() {
  char r[81];
  int i;
  struct termios old,new;
  char c;
  tcgetattr(0,&old);
  new = old;
  new.c_lflag&=~ICANON;
  tcsetattr(0,TCSANOW,&new);
  i = 0;
  while (read(0,&c,1) && c!='\n' && i < 80) r[i++] = c;
  r[i] = 0;
  tcsetattr(0,TCSANOW,&old);
  printf("Entered <%s>\n",r);
  return 0;
}

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