为什么ARGV参数execvp不是const的？ [英] Why is argv parameter to execvp not const?

问题描述

execvp是这样定义：

execvp is defined thus:

int execvp(const char *file, char *const argv[]);

从正在使用precludes code像这样的：

Which precludes code such as this from being used:

const char* argv[] = {"/bin/my", "command", "here", NULL};
execvp(argv[0], argv);

这是一个意外遗漏？它是安全的const_cast会解决此问题？或者做一些execvp实现实际上是在内存潦草？

Was this an accidental omission? Is it safe to const_cast around this? Or do some execvp implementations actually scribble on that memory?

推荐答案

的POSIX规范说（的 http://pubs.opengroup.org/onlinepubs/009604499/functions/exec.html ）：

The POSIX spec says (http://pubs.opengroup.org/onlinepubs/009604499/functions/exec.html):

的的argv [] 和 envp [] 指针数组和字符串到这些阵列点不应通过调用进行修改的Exec功能之一，除了更换处理图像的结果。

The argv[] and envp[] arrays of pointers and the strings to which those arrays point shall not be modified by a call to one of the exec functions, except as a consequence of replacing the process image.

<击>我觉得缺失（或错位）常量只是一个历史怪胎。

I think the missing (or misplaced) const is simply an historical oddity.

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