在字符串数组兼容的指针类型的警告 [英] Incompatible pointer type warnings in array of strings

问题描述

我想出C.字符串数组我有一个字符串数组字典，我补充的话，然后打印出数组，看看它的工作。输出的作品，因为我认为它应该打印在阵列中的话。但我得到一个数字，我无法修复警告。

I am trying out arrays of strings in C. I have a dictionary array of strings, that I add words to and then print out the array to see if it worked. The output works, as i think it should, printing the words in the array. But I get a number of warnings that I am unable to fix.

// 20 word dictionary
#define ROWS 20
#define WORD_LENGTH 10

char dictionary[ROWS][WORD_LENGTH];

void add_word(char **dict, int index, char *word) {
    dict[index] = word;
}

char *get_word(char **dict, int index) {
    return dict[index];
}

void print_dictionary(char **dict) {
    int i;
    for (i = 0; i < 20; i++) {
        printf("%d: %s\n", i, get_word(dict, i));
    }
}

void test_dictionary() {
    add_word(dictionary, 0, "lorem");
    add_word(dictionary, 1, "ipsum");

    print_dictionary(dictionary);
}

int main() {
    test_dictionary();
}

编译此的输出是，

The output of compiling this is,

p5.c: In function ‘test_dictionary’:
p5.c:54:2: warning: passing argument 1 of ‘add_word’ from incompatible pointer type [enabled by default]
p5.c:38:6: note: expected ‘char **’ but argument is of type ‘char (*)[10]’
p5.c:55:2: warning: passing argument 1 of ‘add_word’ from incompatible pointer type [enabled by default]
p5.c:38:6: note: expected ‘char **’ but argument is of type ‘char (*)[10]’
p5.c:57:2: warning: passing argument 1 of ‘print_dictionary’ from incompatible pointer type [enabled by default]
p5.c:46:6: note: expected ‘char **’ but argument is of type ‘char (*)[10]’

我试图改变**字典与dict [行数] [WORD_LENGTH]没有太大的差别。你们能否请您解释如何声明这本词典的参数。谢谢你。

I tried changing **dict to dict[ROWS][WORD_LENGTH] without much difference. Can you guys please explain how to declare this dictionary parameter. Thanks.

编辑：我的编译器标志，CFLAGS = -Wall -g

My compiler flags are, CFLAGS = -Wall -g.

EDIT2：改变了报关单，

Changed the declarations to,

void add_word(char dict[][WORD_LENGTH], int index, char *word) {
    dict[index] = word;
}

char *get_word(char dict[][WORD_LENGTH], int index) {
    return dict[index];
}

void print_dictionary(char dict[][WORD_LENGTH]) {
    int i;
    for (i = 0; i < 20; i++) {
        printf("%d: %s\n", i, get_word(dict, i));
    }
}

这给出了一个编译错误，

This gives a compilation error,

p5.c: In function ‘add_word’:
p5.c:42:14: error: incompatible types when assigning to type ‘char[10]’ from type ‘char *’
make[1]: *** [p5] Error 1

感谢您的一切帮助。

啊！弄清楚了！。因为它是一个指针，我需要使用的strcpy由@Jack的建议。

Ah! Figured it out!. Since it's a pointer, I need to use strcpy as suggested by @Jack.

void add_word(char dict[][WORD_LENGTH], int index, char *word) {
    /*dict[index] = word;*/
    strcpy(dict[index], word);
}

谢谢大家！

推荐答案

根本原因：

数组不是指针！

请注意，有没有从隐式转换字典[] [] 到字典** ，因此错误。当你传递一个阵列功能，它衰变为指针二维数组的第一element.In情况下，第一个元素是单dimenion本身的数组，所以你需要一个指向数组的指针，而不是一个双指针。

Note that there is no implicit conversion from dict[][] to dict ** and hence the error. When you pass a array to a function, it decays as the pointer to its first element.In case of two dimensional array the first element is an array of single dimenion itself and so you need a pointer to an array and not an double pointer.

Soultion：

您需要修改你的函数原型匹配的键入的你逝去。

You need to modify your function prototype to match the type you are passing.

void add_word(char dict[][WORD_LENGTH], int index, char *word);
void print_dictionary(char dict[][WORD_LENGTH]);

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