警告有关从兼容的指针类型的分配使用指针和数组时？ [英] Warning about assignment from incompatible pointer type when using pointers and arrays?

问题描述

对于结构

typedef struct sharedData
{
    sem_t *forks;
}sharedData;

我得到一个警告，当我尝试这样做：

I get a warning when I try to do this:

sharedData sd;
sem_t forks[5];
sd.forks = &forks; // Warning: assignment from incompatible pointer type

我误解或丢失的东西吗？

Am I misunderstanding or missing something?

推荐答案

的问题是，＆放大器;叉的类型为

sem_t (*)[5]

这是一个指针到五年 sem_t 组成的数组。编译器警告是因为 sd.forks 的类型为 sem_t * ，两个指针类型不兑换一另一回事。

That is, a pointer to an array of five sem_ts. The compiler warning is because sd.forks has type sem_t*, and the two pointer types aren't convertible to one another.

要解决这个问题，只是改变了分配

To fix this, just change the assignment to

sd.forks = forks;

因为C的指针/阵列的互换性，为打算在code会工作。这是因为叉会被视为＆放大器;叉[0] ，里面确实有键入 sem_t * 。

Because of C's pointer/array interchangeability, this code will work as intended. It's because forks will be treated as &forks[0], which does have type sem_t *.

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