删除列的文字 [英] Removing Characters of a String
问题描述
我试图写一个code,要求用户输入一个字符串,并采取所有字符,除了字母。
现在我做到了我自己,它似乎并没有正常工作。我是新来的字符串所以我想了解和掌握字符串。我试图在Mac上使用gdb的,但我没有所有的功能明白这一点。
能否请你帮忙吗?
什么是code必须做到:用户输入(例如):ħ**#EL(L)的O& ^ W
和输出你好。
这是我的code:
的#include<&stdio.h中GT;
#包括LT&;&string.h中GT;诠释的main()
{
字符字符串[100];
INT I;
诠释看出= 0; 的printf(请输入字符串:);
scanf函数(%S,字符串); 对于(i = 0;字符串[我] ='\\ 0';!我++)
{
如果(((字符串[1] - ='A'||字符串[I]>Z)及及(字符串[1] - ='A'||字符串[I]>' Z'))||字符串[I]!='\\ 0')
{
看出= 1;
}
其他
看出= 0;
}
如果(看到== 0)
{
的printf(%S,字符串);
}
}
任何部分(除去多余的字符),以改变你code中的字符串。
的#include<&stdio.h中GT;
#包括LT&;&string.h中GT;
#包括LT&;&文件ctype.h GT;字符*过滤器(字符*字符串,INT(*测试)(INT)){
字符*从*到;
对于(从字符串= =; *从++从){
如果(测试(* FROM))
*为++ = * FROM;
}
*为='\\ 0';
返回的字符串;
}诠释主(){
字符字符串[100];
的printf(请输入字符串:);
scanf函数(%99秒,字符串);
的printf(%S \\ n,过滤器(串,因而isalpha)); 返回0;
}
I'm trying to write a code that asks the user to enter a string and takes of all characters except the alphabetical.
Now i did it myself and it doesn't seem to work properly. I'm new to strings so i'm trying to understand and master strings. I tried to use gdb on mac but i don't have all the functions to understand this. Could you please help?
What the code must do: User inputs (for example): h**#el(l)o&^w
and the output is hello.
here is my code:
#include <stdio.h>
#include <string.h>
int main()
{
char string[100];
int i;
int seen = 0;
printf("Enter String: ");
scanf("%s", string);
for (i=0; string[i]!='\0'; i++)
{
if (((string[i]<='a' || string[i]>'z')&&(string[i]<='A' || string[i]>'Z')) ||string[i]!='\0')
{
seen = 1;
}
else
seen = 0;
}
if (seen==0)
{
printf("%s", string);
}
}
No part(remove the extra characters) to change the string in your code.
#include <stdio.h>
#include <string.h>
#include <ctype.h>
char *filter(char *string, int (*test)(int)) {
char *from, *to;
for(to = from = string;*from;++from){
if(test(*from))
*to++ = *from;
}
*to = '\0';
return string;
}
int main(){
char string[100];
printf("Enter String: ");
scanf("%99s", string);
printf("%s\n", filter(string, isalpha));
return 0;
}
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