删除括号外的文字 [英] Remove the text outside the brackets

问题描述

即

$text = 'remove this text (keep this text and 123)';

echo preg_replace('', '', $text);

它应该输出:

(keep this text and 123)

推荐答案

将括号内的任何内容放入一个捕获组并仅保留它，如下所示:

Take anything found within the brackets, put it in a capture group and keep that only, like this:

echo preg_replace('/^.*(\(.*\)).*$/', '$1', $text);

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