解析字符串用逗号和点翻番 [英] Parse strings to double with comma and point

问题描述

我试图写一个字符串数组基本上转换为字符串数组，其中阵列中的所有双打都四舍五入到小数位数我设置的数的函数。此外，还可以在阵列中的字符串这根本没有双重价值。

I am trying to write a function which basically converts an array of strings to an array of strings where all the doubles in the array are rounded to the number of decimalplaces i set. There can also be strings in the array which are no double values at all.

string[,] values = new string[1, 3];

values[0, 0] = "hello";
values[0, 1] = "0.123";
values[0, 2] = "0,123";

int decimalPlaces = 2;

double tmp;
string format = "F" + decimalPlaces.ToString();
IFormatProvider provider = CultureInfo.InvariantCulture;
for (int i = 0; i < values.GetLength(0); i++)
{
    for (int j = 0; j < values.GetLength(1); j++)
    {
        if (double.TryParse(values[i, j], out tmp))
        {
            values[i, j] = tmp.ToString(format, provider);
        }
    }
}

Console.ReadLine();

结果却是：你好，0.12，0.12，但它是你好，123.00，0.12将把逗号以错误的方式。有没有人有这样一个简单而有效的解决方案？

The result has to be: "hello" , "0.12", "0.12" but it is "hello", "123.00", "0.12" will treat the comma in the wrong way. Does anyone have a simple and efficient solution for this?

推荐答案

您想治疗点（。），如逗号（，）。因此，替换

You want to treat dot (.) like comma (,). So, replace

if (double.TryParse(values[i, j], out tmp))

与

if (double.TryParse(values[i, j].Replace('.', ','), out tmp))

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