保存一个TreeView的内容到一个文件，以后加载 [英] Saving content of a treeview to a file and load it later

问题描述

在我的C＃的WinForms程序我有一个只包含父节点（所以，没有孩子的）一个TreeView它像一个列表框，但我需要它，因为巡航能力，如姓名，标签和文本节点的differet属性。

In my C# WinForms program I have a treeview that only contains parent nodes (so, no childs) it is like a listbox but I needed it because of haveing differet properties of nodes like Name, Tag and Text.

没有我希望能够到这个树状的内容保存到一个文件中（基本上是一个文本文件，我把它叫做* .MVIA）。问题是什么是节约节点的所有三个属性中的一个文件，以便它可以再次加载的最佳方式后是否正确？

No I want to be able to save the content of this treeview into a file (Basically a text file which I call it *.MVIA). The question is what is the best way to save all three properties of nodes in a file so it can loaded again later properly?

在我来到这个想法的时刻：

At the moment I came with this idea :

    private void menuFileSave_Click(object sender, EventArgs e)
    {
        StringBuilder sb = new StringBuilder();

        foreach(TreeNode node in treeViewFiles.Nodes)
        {
            sb.AppendLine(node.Name);
        }

        SaveFileDialog saveList = new SaveFileDialog();

        saveList.DefaultExt = "*.mvia";
        saveList.Filter = "MVIA Files|*.mvia";

        if (saveList.ShowDialog() == DialogResult.OK)
        {
            File.WriteAllText(saveList.FileName, sb.ToString());
        }            
    }

正如你所看到的，每个节点的每个Name属性将被保存在一条线上。现在我还需要添加它的文本和标签属性，但后来我有麻烦回读（老实说，我不知道如何）。

As you can see, each Name property of each node will be saved in a line. Now I need to add its Text and Tag property also, but later I have trouble reading it back (Honestly I don't know how to).

你能给我一些想法是什么，以节省每一个节点的全部三个属性，并且能够很容易地加载一个最好的办法以后呢？

Would you give me some ideas what is a best way to save all three property of each node and be able to load it easily later?

感谢。

推荐答案

您可以使用BinaryFormatter的序列化到/反序列化的节点

You can use BinaryFormatter to Serialize/Deserialize Nodes

    public static void SaveTree(TreeView tree, string filename)
    {
        using (Stream file = File.Open(filename, FileMode.Create))
        {
            BinaryFormatter bf = new BinaryFormatter();
            bf.Serialize(file, tree.Nodes.Cast<TreeNode>().ToList());
        }
    }

    public static void LoadTree(TreeView tree, string filename)
    {
        using (Stream file = File.Open(filename, FileMode.Open))
        {
            BinaryFormatter bf = new BinaryFormatter();
            object obj = bf.Deserialize(file);

            TreeNode [] nodeList = (obj as IEnumerable<TreeNode>).ToArray();
            tree.Nodes.AddRange(nodeList);
        }
    }

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