如何算组特定字符串中的字符 [英] How to count sets of specific characters in a string

问题描述

基本上，我要算组特定字符的字符串。
换句话说，我需要计算所有的字母和数字，而不是其他。
，而我似乎无法找到合适的（正则表达式）语法。
这是我有...

Basically, I want to count sets of specific characters in a string. In other words I need to count all Letters and Numbers, and nothing else. But I cant seem to find the right (regex) syntax. Here's what i have ...

public double AlphaNumericCount(string s)
{
    double count = Regex.Matches(s, "[A-Z].[a-z].[0-9]").Count;
        return count;
}

我一直在四处寻找，但不能似乎发现了什么，让更多不止一个字符集。
同样，我不知道语法的，也许它应该是
[A-Z] / [A-Z] / [0-9]
或什么的。 Anywho，宽容我。 - 使用正则表达式了我的第一天

I've been looking around, but cant seem to find anything that allows more than one set of characters. Again, I'm not sure on the syntax maybe it should be "[A-Z]/[a-z]/[0-9]" or something. Anywho, go easy on me - its my first day using Regex.

感谢

推荐答案

正则表达式小抄

快报正则表达式工具

[AZ]。[AZ] [0-9] 将匹配任何大写字母（ [AZ] ），其次为任意字符（。），其次是任何小写字母（ [AZ] ），其次是任何字符（。），后跟任意数量的（ [0-9] ）。

[A-Z].[a-z].[0-9] will match any capital letter ([A-Z]), followed by any character (.), followed by any lower case letter ([a-z]), followed by any character (.), followed by any number ([0-9]).

要匹配任何字母或数字是什么 [A-ZA-Z0-9] 。

What you want to match on any letter or number is [A-Za-z0-9].

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