删除指向const的指针(T const *) [英] Deleting a pointer to const (T const*)
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问题描述
我有一个关于const指针的基本问题。我不允许使用const指针调用任何非const成员函数。但是,我允许这样做一个const指针:
delete p;
这将调用类的析构函数,它本质上是一个非常量'方法'。为什么这是允许的?只是支持这个:
删除这个;
还是有其他原因?
解决方案
它支持:
//动态创建不能更改的对象
const Foo * f = new Foo;
//这里使用const成员函数
//删除它
delete f;但是请注意,问题不限于动态创建的对象:
{
const Foo f;
//使用它
} //析构函数在这里调用
不是在const对象上调用,我们根本不能使用const对象。
I have a basic question regarding the const pointers. I am not allowed to call any non-const member functions using a const pointer. However, I am allowed to do this on a const pointer:
delete p;
This will call the destructor of the class which in essence is a non-const 'method'. Why is this allowed? Is it just to support this:
delete this;
Or is there some other reason?
解决方案 It's to support:
// dynamically create object that cannot be changed
const Foo * f = new Foo;
// use const member functions here
// delete it
delete f;
But note that the problem is not limited to dynamically created objects:
{
const Foo f;
// use it
} // destructor called here
If destructors could not be called on const objects we could not use const objects at all.
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