如何写`is_complete`模板? [英] How to write `is_complete` template?
问题描述
回答这个问题后,我试图找到在Boost库中的is_complete
模板,我意识到在Boost.TypeTraits中没有这样的模板。为什么Boost库中没有这样的模板?它应该是什么样子?
//!检查类型是否完整
模板< typename T>
struct is_complete
{
static const bool value =(sizeof(T)> 0);
};
...
//所以我可以这样使用它
BOOST_STATIC_ASSERT(boost :: is_complete< T> :: value);
上述代码不正确,因为应用 sizeof
为不完整类型。
那么,什么是好的解决方案?这个问题一般不能在不违反 ODR规则的情况下解决,但是有一个特定的平台解决方案,适用于我。
code> namespace
{
template< class T,int discriminator>
struct is_complete {
static T& getT();
static char(& pass(T))[2];
static char pass(...);
static const bool value = sizeof(pass(getT()))== 2;
};
}
#define IS_COMPLETE(X)is_complete< X,__ COUNTER __> :: value
很遗憾, COUNTER 预定义宏不是标准的一部分,因此不会在每个编译器上工作。
After answering this question I was trying to find is_complete
template in Boost library and I realized that there is no such template in Boost.TypeTraits. Why there is no such template in Boost library? How it should look like?
//! Check whether type complete
template<typename T>
struct is_complete
{
static const bool value = ( sizeof(T) > 0 );
};
...
// so I could use it in such a way
BOOST_STATIC_ASSERT( boost::is_complete<T>::value );
The code above is not correct, because it is illegal to apply sizeof
to an incomplete type. What will be a good solution? Is it possible to apply SFINAE in this case somehow?
Well, this problem couldn't be solved in general without violating the ODR rule, but there is there a platform specific solution which works for me.
The answer given by Alexey Malistov can be used on MSVC with a minor modification:
namespace
{
template<class T, int discriminator>
struct is_complete {
static T & getT();
static char (& pass(T))[2];
static char pass(...);
static const bool value = sizeof(pass(getT()))==2;
};
}
#define IS_COMPLETE(X) is_complete<X,__COUNTER__>::value
Unfortunately, the COUNTER predefined macro is not part of the standard, so it would not work on every compiler.
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