如何拆分vc ++中的字符串？ [英] How to split the strings in vc++?

问题描述

我有一个字符串stack + ovrflow * newyork;我必须拆分这个堆栈，溢出，newyork

I have a string "stack+ovrflow*newyork;" i have to split this stack,overflow,newyork

任何想法

推荐答案

首先，如果可用，我总是使用boost :: tokenizer来执行这种任务（参见下面的优秀答案）。

First and foremost if available, I would always use boost::tokenizer for this kind of task (see and upvote the great answers below)

boost，你有几个选项：

Without access to boost, you have a couple of options:

您可以使用C ++ std :: strings并使用stringstream和getline（最安全的方式）解析它们

You can use C++ std::strings and parse them using a stringstream and getline (safest way)

std::string str = "stack+overflow*newyork;";
std::istringstream stream(str);
std::string tok1;
std::string tok2;
std::string tok3;

std::getline(stream, tok1, '+');
std::getline(stream, tok2, '*');
std::getline(stream, tok3, ';');

std::cout << tok1 << "," << tok2 << "," << tok3 << std::endl

或者你可以使用strtok家族的函数

Or you can use one of the strtok family of functions (see Naveen's answer for the unicode agnostic version; see xtofls comments below for warnings about thread safety), if you are comfortable with char pointers

char str[30]; 
strncpy(str, "stack+overflow*newyork;", 30);

// point to the delimeters
char* result1 = strtok(str, "+");
char* result2 = strtok(str, "*");
char* result3 = strtok(str, ";");

// replace these with commas
if (result1 != NULL)
{
   *result1 = ',';
}
if (result2 != NULL)
{
   *result2 = ',';
}

// output the result
printf(str);

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