如何将sockaddr结构转换为sockaddr_in - C ++网络套接字ubuntu UDP [英] how do you cast sockaddr structure to a sockaddr_in - C++ networking sockets ubuntu UDP

问题描述

我想获得客户端地址，但是我不确定如何将sockaddr结构转换为sockaddr_in？

I am trying to get the client address, but i am unsure how do i cast the sockaddr structure to sockaddr_in?

struct sockaddr_in cliAddr, servAddr;

    n = recvfrom(sd, msg, MAX_MSG, 0,(struct sockaddr *) cliAddr,sizeof(cliAddr));

 //i tried this but it does not work
    struct sockaddr cliSockAddr = (struct sockaddr *) cliAddr; 
    char *ip = inet_ntoa(cliSockAddr.sin_addr);

提前感谢！ ：）

我发现了让我进入这一步的问题：
从sockaddr结构获取IPV4地址

i've found questions that brought me to this step: Getting IPV4 address from a sockaddr structure

对不起，为了避免混淆，这是我真正的实现，其中ci是存储指针的对象，如sockaddr_in。

Sorry to avoid confusion, this is my real implementation where "ci" is an object to store pointers such as sockaddr_in.

    /* receive message */
    n = recvfrom(*(ci->getSd()), msg, MAX_MSG, 0,(struct sockaddr *) ci->getCliAddr(),ci->getCliLen());

    char *ip = inet_ntoa(ci->getCliAddr().sin_addr);

我会收到以下错误：

udpserv.cpp:166: error: request for member ‘sin_addr’ in ‘ci->clientInfo::getCliAddr()’, which is of non-class type ‘sockaddr_in*’

推荐答案

其实很简单！

struct sockaddr *sa = ...;

if (sa->sa_family == AF_INET)
{
    struct sockaddr_in *sin = (struct sockaddr_in *) sa;
    ip = inet_ntoa(sin->sin_addr);
}

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