C ++，为什么array = ptr legal？ [英] C++, why is array=ptr legal?

问题描述

最近我看到这段代码。此行是否是编译错误？ char arr [4] =Abc;

是arr是指针吗？是char *复制到堆栈中的数组吗？这是合法的在所有版本的C + +（和什么关于C？）。我测试和看到这个工作在VS和代码垫，我相信使用gcc

-edit-只是为了乐趣，我试图用静态const char *替换Abc。它给我一个无效的初始化程序错误。

  int main（）
 {
 int j = 97; 
 char arr [4] =Abc; 
 printf（arr，j）; 
 getch（）; 
 return 0; 
} 
  

解决方案

array = ptr 不是合法赋值（如果数组有数组类型并且 ptr 具有相应的指针类型）。在你已经显示的代码中， = 引入了一个初始化器，因为它是一个声明的一部分。

使用字符串常量初始化 char 的数组是合法的。 p>

Recently i saw this piece of code. Shouldnt this line be a compile error?char arr[4]="Abc";

What happens here? Is arr a pointer? is the char* copied into an array on stack? is this legal in all version of C++ (and what about C?). I tested and seen this works in VS and code pad which i believe uses gcc

-edit- Just for fun I tried replacing "Abc" with a static const char *. It gave me an invalid initializer error.

int main()
{
    int j=97;
    char arr[4]="Abc";
    printf(arr,j);
    getch();
    return 0;
}

解决方案

array = ptr is not a legal assignment (if array has an array type and ptr has the corresponding pointer type). In the code you have shown, though, the = introduces an initializer as it is part of a declaration. It is not an assignment.

It is legal to initialize an array of char with a string constant.

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