constexpr(gcc)错误:在'{'token之前不允许包含括号的初始化程序 [英] Error with constexpr(gcc) - error: a brace-enclosed initializer is not allowed here before '{' token
问题描述
struct X {
constexpr static char a1[] = "hello"; // Okay
constexpr static const char* a2[] = {"hello"}; // Error
};
int main(){}
使用gcc编译时出现错误:
Compiling with gcc gives the error:
错误:在'{'token
error: a brace-enclosed initializer is not allowed here before '{' token
这是非法使用constexpr吗?
Is this an illegal use of constexpr?
EDIT
我试过3个不同版本的gcc,它编译在最新的4.7.0我有(我只是下载它,我使用mingw-w64),所以它看起来是一个修复的bug
I tried 3 different versions of gcc, and it compiled on the newest 4.7.0 I have (I just downloaded it, I'm using mingw-w64), so it looks to be a fixed bug (a link to the bug would be nice though!).
4.7.0 20120311(prerelease)//好了
4.6.4 20120305(prerelease)//错误
4.7.0 20110829(实验性)//错误
4.7.0 20120311 (prerelease) // Okay
4.6.4 20120305 (prerelease) // Error
4.7.0 20110829 (experimental) // Error
推荐答案
这是一个已修复的错误。我已经确认代码编译与 g ++ 4.7.0 20120311(prerelease)
。
This is a bug which has been fixed. I have confirmed that the code compiles with g++ 4.7.0 20120311 (prerelease)
.
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