从AppExceptionHandler渲染视图 [英] Render View from AppExceptionHandler

问题描述

我正在使用CakePHP 2.0并想要处理一个ForbiddenException。
我按照

I'm working with CakePHP 2.0 and want to handle a ForbiddenException. I've followed the example explained at the CakePHP Cookbook.

我的异常现在被捕获在AppExceptionHandler，但我不知道如何从这里移动。我想呈现相关的视图，但 $ this 不可用。
任何人都有起点吗？

My exception is now caught at the AppExceptionHandler but I don't know how to move from here. I want to render a relevant View but $this is not available. Does anyone have a starting point for me?

编辑：

我的代码到目前为止到Cookbook示例：

My code so far is identical to the Cookbook example:

在app / Config / core.php中

In app/Config/core.php

Configure::write('Exception.handler', 'AppExceptionHandler::handle');

在app / Config / bootstrap.php

In app/Config/bootstrap.php

App::uses('AppExceptionHandler', 'Lib');

在app / Lib / AppExecptionHandler.php

In app/Lib/AppExecptionHandler.php

class AppExceptionHandler {
    public static function handle($error) {
        if($error instanceOf ForbiddenException ){
            echo 'Oh noes! ' . $error->getMessage();
            // $this->Session->setFlash('To access the page please login');     
        }
    }
}

Bart

推荐答案

正如您在评论中提到的，您可以将错误视图的副本复制到您自己的视图文件夹并控制渲染。

As you mentioned on your comment, you can make copies of the error views to your own View folder and control the rendering.

如果您还想使用会话，请记住，在应用程序的任何部分，您可以使用 CakeSession 也可以访问会话。

If you want to use the session as well, remember that, in any part of your application, you can use CakeSession to access the session as well.

http://book.cakephp.org/2.0/en/development/sessions.html#reading-writing-session-data

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