BAD_INSTRUCTION在swift闭包 [英] BAD_INSTRUCTION within swift closure

问题描述

func loadMe() -> Void {
    println(me.initUrl());

    let url:NSURL = NSURL(string:me.initUrl())
    let request:NSURLRequest = NSURLRequest(URL:url)
    let queue:NSOperationQueue = NSOperationQueue()

    NSURLConnection.sendAsynchronousRequest(request, queue:queue, completionHandler:{response, data, error in
        if data {
            var jerr:NSError?
            var json:NSDictionary = NSJSONSerialization.JSONObjectWithData(data, options:NSJSONReadingOptions.MutableContainers, error:&jerr) as NSDictionary

            if !jerr {
                println(json.description)
                let time:String = json.valueForKey("time") as String
                println(time)

                //  self.me.setDictionary(json)
            }
        }
    })
}

上面的代码工作正常，想要将值从NSDictionary分配给变量。

The code above works fine up to the point where i want to assign a value from an NSDictionary to a variable.

let time:String = json.valueForKey("time") as String 

后跟EXC_BAD_INSTRUCTION（代码= EXC_I386_INVOP，子代码= 0x0），但

is followed by EXC_BAD_INSTRUCTION(code=EXC_I386_INVOP,subcode=0x0) but

println(json.description) 

打印出一个有效的NSDictionary。有没有人知道这个问题的解决方案？

prints out a valid NSDictionary. Does anybody know a solution to this problem?

推荐答案

我解决了我的问题，转换到正确的类型的原始NSDictionary值后我意识到不是NSDictionary的所有值都是NSStrings。如果您的服务返回类似于此的混合类型JSON对象

I solved my problem with casting to the correct type of the original NSDictionary value after i realised that not all values of the NSDictionary were NSStrings. If your service returns a mixed type JSON object like this

{"id":2, "name":"AC Vent Temp", ...}

你必须获取这样的值。

var id:int = sensor.valueForKey("id") as Int;
var name:String? = sensor.valueForKey("name") as String;

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