更好的地图构造函数 [英] Better Map Constructor

问题描述

是否有更精简的方法来执行以下操作？

Is there a more streamlined way to do the following?

Map<String, String> map = new HashMap<String, String>();
map.put("a", "apple");
map.put("b", "bear");
map.put("c", "cat");

我在找更接近这个的地方。

I'm looking for something closer to this.

 Map<String, String> map = MapBuilder.build("a", "apple", "b", "bear", "c", "cat");

推荐答案

不，没有，方法做到这一点，受到Objective-C NSDictionary类的启发：

No, there isn't, but I wrote a method to do exactly this, inspired by Objective-C NSDictionary class:

public static Map<String, Object> mapWithKeysAndObjects(Object... objects) {

    if (objects.length % 2 != 0) {
        throw new IllegalArgumentException(
                "The array has to be of an even size - size is "
                        + objects.length);
    }

    Map<String, Object> values = new HashMap<String, Object>();

    for (int x = 0; x < objects.length; x+=2) {
      values.put((String) objects[x], objects[x + 1]);
    }

    return values;

}

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