如何在sed中匹配多个地址？ [英] How do I match multiple addresses in sed?

问题描述

我想对与和或匹配的任何行执行一些 sed 命令>或的多个命令：例如 sed '50，70 / abc / d'将删除匹配 / abc / 的<70,70 ，或者 sed -e '10，20s / regex /'-e '30,40s / complex / regex / ，而无需重新输入 s / compicated / regex /

解决方案

逻辑和

和部分可以使用大括号：

  sed '50，70 {/ abc / d;}'
  

此外，大括号可以嵌套多个和条件。 / p>



（以上是在GNU sed 下测试的BSD sed

逻辑或

或部分可以用分支处理：

  sed -e '10，20 {b cr; }'-e '30，40 {b cr;}'-eb -e：cr -e's / complex / regex /'file 
  

• 10,20 {b cr;}

  
  
  

  对于从10到20的所有行，我们分支到 cr




• 30,40 {b cr;}

  
  
  

  对于从30到40的所有行， c $ c> cr




• b

  
  
  

  对于所有其他行，我们跳过其余的命令。




• ：cr

  
  
  

  这标记了标签 cr




• s / complex / regex /

  
  
  

  code> cr 。





，上面的语法可以缩短为：

  sed '10， b cr}; 30,40 {b cr}; b; ：cr; s / complex / regex /'文件
  

I want to execute some sed command for any line that matches either the and or or of multiple commands: e.g., sed '50,70/abc/d' would delete all lines in range 50,70 that match /abc/, or a way to do sed -e '10,20s/complicated/regex/' -e '30,40s/complicated/regex/ without having to retype s/compicated/regex/

解决方案

Logical-and

The and part can be done with braces:

sed '50,70{/abc/d;}'

Further, braces can be nested for multiple and conditions.

(The above was tested under GNU sed. BSD sed may differ in small but frustrating details.)

Logical-or

The or part can be handled with branching:

sed -e '10,20{b cr;}' -e '30,40{b cr;}' -e b -e :cr -e 's/complicated/regex/' file

• 10,20{b cr;}

  For all lines from 10 through 20, we branch to label cr

• 30,40{b cr;}

  For all lines from 30 through 40, we branch to label cr

• b

  For all other lines, we skip the rest of the commands.

• :cr

  This marks the label cr

• s/complicated/regex/

  This performs the substitution on lines which branched to cr.

With GNU sed, the syntax for the above can be shortened a bit to:

sed '10,20{b cr}; 30,40{b cr}; b; :cr; s/complicated/regex/' file

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