比较JavaScript对象数组以获取最小/最大值 [英] Compare JavaScript Array of Objects to Get Min / Max

问题描述

我有一个对象数组，我想比较这些对象在一个特定的对象属性。这是我的数组：

I have an array of objects and I want to compare those objects on a specific object property. Here's my array:

var myArray = [
    {"ID": 1, "Cost": 200},
    {"ID": 2, "Cost": 1000},
    {"ID": 3, "Cost": 50},
    {"ID": 4, "Cost": 500}
]

和获得最小和最大值。我意识到我可以只抓取成本值，推送到一个javascript数组，然后运行快速JavaScript最大/最小。

I'd like to zero in on the "cost" specifically and a get a min and maximum value. I realize I can just grab the cost values and push them off into a javascript array and then run the Fast JavaScript Max/Min.

但是有一个更简单的方法，通过绕过中间的数组步骤

However is there an easier way to do this by bypassing the array step in the middle and going off the objects properties (in this case "Cost") directly?

推荐答案

在这种情况下，最快的方式是循环遍历所有元素，并将其与最高/最低值进行比较。

The fastest way, in this case, is looping through all elements, and compare it to the highest/lowest value, so far.

（创建数组，调用数组方法对于此简单操作）。

(Creating an array, invoking array methods is overkill for this simple operation).

 // There's no real number bigger than plus Infinity
var lowest = Number.POSITIVE_INFINITY;
var highest = Number.NEGATIVE_INFINITY;
var tmp;
for (var i=myArray.length-1; i>=0; i--) {
    tmp = myArray[i].Cost;
    if (tmp < lowest) lowest = tmp;
    if (tmp > highest) highest = tmp;
}
console.log(highest, lowest);

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