如何测试一些代码不能在C ++中编译？ [英] How to test that some code doesn't compile in C++?

问题描述

可能重复：

单元测试编译时错误

如果它可以写一种单元测试，这将验证给定的代码不编译。

I'm wondering if its possible to write a kind of unit test which will verify that a given code doesn't compile.

例如，我有一个模板类：

For example, I have a template class:

#include <boost/static_assert.hpp>
#include <boost/type_traits/is_base_of.hpp>

struct bar_base {};

template <typename T>
class foo 
{
    BOOST_STATIC_ASSERT(::boost::is_base_of<T, bar_base>::value);
};

所以，测试应该成功：

struct bar_derived : bar_base {};
foo<bar_derived> f;

，但应该失败：

struct bar_other {};
foo<bar_other> f;

任何想法如何实现这样的行为？ （现在，我必须取消注释失败的代码，并手动验证是否有编译错误 - 我想避免这种情况）

Any ideas how to achieve such a behaviour? (For now, I have to uncomment the failing code and verify manually that there are compile errors - I want to avoid that)

推荐答案

Boost有编译测试，他们通过简单地将每个测试放入一个单一的源文件，然后尝试编译每一个。 Boost.Build 支持运行测试的特殊命令，包括测试文件是否编译。

Boost does have compilation tests, and they do this by simply putting each of these tests into a single source-file and then try to compile each of these. Boost.Build supports special commands to run tests, which include testing if a file compiles or not.

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