Swift NSPredicate在复合语句时抛出EXC_BAD_ACCESS(Code = 1,address = 0x1) [英] Swift NSPredicate throwing EXC_BAD_ACCESS(Code=1, address=0x1) when compounding statements
问题描述
这里是错误发生的文件
class LevelsScreenModel:UIViewController {
func getWord(level:Int,section:Int) - > String
{
let fetchRequest = NSFetchRequest(entityName:Words)
//这是发生错误的行
fetchRequest.predicate = NSPredicate :level =%@,level)
fetchRequest.predicate = NSPredicate(format:section =%@,section)
let word = AppDelegate()。managedObjectContext!.executeFetchRequest (fetchRequest,error:nil)as [Words]
if(word.count> 1)
{
for word in
{
println(words.word)
return words.word
}
}
returnERROR
}
}
解决方案 %@
谓词格式字符串中的占位符用于Objective-C
对象,因此您必须将整数包装到 NSNumber
:
fetchRequest.predicate = NSPredicate(format:level =%@,NSNumber(integer:level))
pre>
或使用 ld
代替格式化一个(长整数):
fetchRequest.predicate = NSPredicate(format:level =%ld,level)
注意
fetchRequest.predicate = NSPredicate(format:...)
fetchRequest.predicate = NSPredicate(format:...)
创建复合谓词,秒分配只需
覆盖第一个。您可以使用 NSCompoundPredicate
:
let p1 = NSPredicate level =%ld,level)!
let p2 = NSPredicate(format:section =%ld,section)!
fetchRequest.predicate = NSCompoundPredicate.andPredicateWithSubpredicates([p1,p2])
AND的谓词:
fetchRequest.predicate = NSPredicate(format:level =%ld AND section =%ld ,level,section)
I am trying to use NSPredicate in Swift to query Core Data but it throws an EXC_BAD_ACCESS(Code=1, address=0x1) error when trying to run it, what am I doing wrong?
Here is the file where the error happens
class LevelsScreenModel : UIViewController {
func getWord(level: Int, section: Int) -> String
{
let fetchRequest = NSFetchRequest(entityName: "Words")
//This is the line where the error happens
fetchRequest.predicate = NSPredicate(format: "level = %@", level)
fetchRequest.predicate = NSPredicate(format: "section = %@", section)
let word = AppDelegate().managedObjectContext!.executeFetchRequest(fetchRequest, error: nil) as [Words]
if(word.count > 1)
{
for words in word
{
println(words.word)
return words.word
}
}
return "ERROR"
}
}
解决方案 The %@
placeholder in predicate format strings is for Objective-C
objects, so you have to wrap the integer into an NSNumber
:
fetchRequest.predicate = NSPredicate(format: "level = %@", NSNumber(integer: level))
or use ld
instead to format a (long) integer:
fetchRequest.predicate = NSPredicate(format: "level = %ld", level)
Note also that
fetchRequest.predicate = NSPredicate(format: ...)
fetchRequest.predicate = NSPredicate(format: ...)
does not create a compound predicate, the seconds assignment simply
overwrites the first. You can use an NSCompoundPredicate
:
let p1 = NSPredicate(format: "level = %ld", level)!
let p2 = NSPredicate(format: "section = %ld", section)!
fetchRequest.predicate = NSCompoundPredicate.andPredicateWithSubpredicates([p1, p2])
or simply combine the predicates with "AND":
fetchRequest.predicate = NSPredicate(format: "level = %ld AND section = %ld", level, section)
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