提交表单的问题...回车键 [英] Submit Form problem... Enter key

问题描述

我有一个包含几滴列表和文本字段的表单，和一个按钮...

I have a form containing several drop lists and a text field, and a button...

当我按一下按钮，一个ajaxfunction叫...阿贾克斯然后调用一个PHP函数，它从一个MySQL数据库得到的结果......

When I click the button, an ajaxfunction is called... the ajax then calls a php function which gets results from a mysql db...

问题是，我不能做同样的事情，只需打的形式进入，页面只是被刷新......

The problem is that I cant do the same thing by just hitting enter in the form, the page just gets refreshed...

这说明，我认为形式被提交，但忽略ajaxfunction按下回车键的时候，即使我有的onsubmit =AjaxFunction（）;的形式标记...

That explained, I think the form gets submitted, but ignores the ajaxfunction when hitting enter, EVEN though i have " onSubmit="AjaxFunction();" in the form tag...

任何想法？

有谁知道一个办法忽略的形式提交按下回车键的时候？也许，而不是按一下按钮按下回车键的时候？

Does anybody know a way to ignore the form submit when hitting enter? and maybe instead click the button when hitting enter?

谢谢...

推荐答案

改变你的onsubmit到的onsubmit =返回AjaxFunction（）;并返回false从AjaxFunction。这将prevent的形式从submiting。

change your onsubmit to onsubmit="return AjaxFunction();" and return false from your AjaxFunction. That will prevent the form from submiting.

这篇关于提交表单的问题...回车键的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！