检测java中的回车键 [英] Detecting enter key in java

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本文介绍了检测java中的回车键的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我尝试使用扫描仪获取用户输入,如果用户按Enter键,则继续执行下一个输入语句。但它一次打印。

I have tried to get user input with scanner and if user press enter then proceed to next input statement. but it print all at once.

public class MainRDS 
{
    public static void main(String[] args) 
    {
        Scanner in = new Scanner(System.in);
        String path;
        String name;
        String ext;
        String date;

        System.out.println("Directory search by path, name, extension, content and date.");
        System.out.print("\nEnter Starting directory for the search (link c:"+"\\"+"temp) : ");
        path = in.next();

        System.out.print("\nEnter the file name (like myFile or enter for all) : ");

        if((name = in.nextLine()).length() > 0)
        System.out.print("\nEnter the file extenstion (like txt or enter for all) : ");

        if((ext = in.nextLine()).length() > 0)
        System.out.print("\nEnter last modified date (like 11/21/2012 or enter for any) : ");

        date = in.nextLine();
    }
}

输出:

Directory search by path, name, extension, content and date.

Enter Starting directory for the search (link c:\temp) : c:

Enter the file name (like myFile or enter for all) : myfile

Enter last modified date (like 11/21/2012 or enter for any) : 

必需输出:

Directory search by path, name, extension, content and date.  
Enter starting directory for the search (like c:\temp): c:\temp 
Enter the file name (like myFile or enter for all):  
Enter the file extension (like txt or enter for all): txt 
Enter content to search for (like comp121 or enter for any):  
Enter last modified date (like 11/21/2013 or enter for any): 11/1/2011 


推荐答案

知道了!

您需要使用:

path = in.nextLine();

否则, name = in.nextLine()捕获路径的输入键并且没有任何值。

Otherwise, name = in.nextLine() catches the path's "enter" key and doesn't get any value.

这篇关于检测java中的回车键的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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