Cuda推力定制功能 [英] Cuda Thrust Custom function

问题描述

如何在Thrust中实现此功能？

How can I impliment this function in Thrust?

for (i=0;i<n;i++)
    if (i==pos)
        h1[i]=1/h1[i];
    else
        h1[i]=-h1[i]/value;

在CUDA中，我喜欢：

In CUDA I did it like:

__global__ void inverse_1(double* h1, double value, int pos, int N)
{
    int i = blockDim.x * blockIdx.x + threadIdx.x;
    if (i < N){
        if (i == pos)
            h1[i] = 1 / h1[i];
        else
            h1[i] = -h1[i] / value;
    }
}

谢谢！

推荐答案

您需要创建一个二进制函子来应用操作，然后使用计数迭代器作为第二个输入。你可以将 pos 和 value 传递给函子的构造函数。它看起来像：

You need to create a binary functor to apply the operation, then use a counting iterator as the second input. You can pass pos and value into the functor's constructor. It'd look something like:

struct inv1_functor
{
  const int pos;
  const double value;

  inv1_functor(double _value, int _pos) : value(_value), pos(_pos) {}

  __host__ __device__
  double operator()(const double &x, const int &i) const {
    if (i == pos)
      return 1.0/x;
    else
      return -x/value;
  }
};

//...

thrust::transform(d_vec.begin(), d_vec.end(), thrust::counting_iterator<int>(),  d_vec.begin(), inv1_functor(value, pos));

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