在d3甘特图中绘制代表当前日期的垂直线 [英] Draw a vertical line representing the current date in d3 gantt chart
问题描述
hi这可能很容易为你们我只需要绘制一条垂直线代表当前日期在我的d3甘特图。我已经找出了我的值只是有麻烦在我的X的值,因为im在我的x轴使用time.scale。粘贴绘制我的甘特图的代码,绘制我的垂直线的部分位于底部
hi this maybe very easy for you guys i just need to draw a vertical line that represents the current date in my d3 gantt chart. i already figure out the values for my y i just having trouble in the value in my X because im using a time.scale in my x-axis. ill paste the codes that draws my gantt chart and the part where i draw my vertical line is located at the very bottom
initTimeDomain(tasks);
initAxis();
var numFormat = d3.format(",.0f");
var dateFormat = d3.time.format("%Y-%b-%d");
var parseDate = d3.time.format("%Y-%b-%d").parse;
var svg = d3.select("#gantt_chart")
.append("svg")
.attr("class", "chart")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("class", "gantt-chart")
.attr("width", width + margin.left + margin.right)
.attr("height", (height + margin.top + margin.bottom) / tasks[tasks.length - 1].endDate)
.attr("transform", "translate(" + margin.left + ", " + margin.top + ")");
//this is the x-axis
svg.append("g")
.attr("class", "x axis")
.attr("transform", "translate(0, " + (height - margin.top - margin.bottom) + ")")
.transition()
.call(xAxis)
.selectAll("text")
.style("text-anchor","end")
//.attr("dx", 35)
//.attr("dy", 5);
.attr("dx", "-.8em")
.attr("dy", -10)
.attr("transform", function(d){return "rotate(-90)"});
//this is the y-axis
svg.append("g").attr("class", "y axis").transition().call(yAxis);
//this is the actual gantt
svg.selectAll(".chart")
.data(tasks, keyFunction).enter()
.append("rect")
.attr("rx", 0)
.attr("ry", 0)
.attr("class", function(d){
if(d.status > 70)
{
return "bar-failed";
}
else if (d.status >= 51 && d.status <= 70){
return "bar-killed";
}
else{
return "bar-running";
}
})
.attr("y", 0)
.attr("transform", rectTransform)
.attr("height", function(d) { return y.rangeBand(); })
.attr("width", function(d) {
return (x(d.endDate) - x(d.startDate));
})
.on("mouseover", function(d){
div.transition()
.duration(200)
.style("opacity", .9);
div.html("HandlerID: " + d.taskName + "<br>" + "startDate: " + dateFormat(d.startDate) + "<br/>" +
"endDate: " + dateFormat(d.endDate) + "<br/>" + "% Insertions: " + d3.round(d.status,2) + "%" + "<br/>" +
"Insertions: " + numFormat(d.insertions) )
.style("left", (d3.event.pageX) + "px")
.style("top", (d3.event.pageY - 28) + "px");
})
.on("mouseout",function(d){
div.transition()
.duration(500)
.style("opacity", 0);
});
var today = new Date();
var dd = today.getDate();
var mm = today.getMonth()+1; //January is 0!
var yyyy = today.getFullYear();
if(dd<10) {
dd='0'+dd
}
if(mm<10) {
mm='0'+mm
}
today = yyyy+'-'+mm+'-'+dd;
today = parseDate(today);
//document.write(today);
svg.append("line")
.attr("x1", today)
.attr("y1", 0)
.attr("x2", today)
.attr("y2", height - margin.top - margin.bottom)
.style("stroke-width", 2)
.style("stroke", "red")
.style("fill", "none");
推荐答案
无需获取其日期,月和年,因为它将返回一个字符串。
所有你需要做的是将你的 x
变量的日期放到jive的域中
Just get the date today. No need to get its date, month, and year because it will return a string.
All you have to do is put the date in your x
variable to jive with its domain
var today = new Date();
var dd = today.getDate(); //<<===== no need
var mm = today.getMonth()+1; //January is 0! //<<===== no need
var yyyy = today.getFullYear(); //<<===== no need
svg.append("line")
.attr("x1", x(today)) //<<== change your code here
.attr("y1", 0)
.attr("x2", x(today)) //<<== and here
.attr("y2", height - margin.top - margin.bottom)
.style("stroke-width", 2)
.style("stroke", "red")
.style("fill", "none");
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