无法登录到所需的位置 [英] not able to login to the desired location

问题描述

可能重复：

未定义索引：C：\wamp\www\Website\storeadmin\admin_login.php..中的用户名密码

  // admin_login。 php 
<？php 
 session_start（）; 
 if（isset（$ _ SESSION [member]））{
 header（location：index.php）; 
 exit（）; 
} 
 
？> 
<？php 
 if（isset（$ _ POST [username]）&&& isset（$ _ POST [password]））{//<  - 检查用户是否点击按钮
 $ manager = preg_replace（'＃[A-Za-z0-9] #i'，，$ _ POST [username]）; 
 $ password = preg_replace（'＃[A-Za-z0-9] #i'，，$ _ POST [password]）; 
 
 
 
包括../storescripts/connect_to_mysql.php; 
 $ sql = mysql_query（SELECT * FROM admin WHERE username ='$ manager'AND password ='$ password'LIMIT 1）; 
 $ exists_count = mysql_num_rows（$ sql）; 
 if（$ exists_count == 1）{
 while（mysql_fetch_array（$ sql））{
 $ id = $ row [id]; 
} 
 
 $ _SESSION [id] = $ id; 
 $ _SESSION [manager] = $ manager; 
 $ _SESSION [password] = $ password; 
 header（location：index.php）; 
 exit（）; 
 
} 
 else {
 echo'此信息不正确，请重试< a href =index.php>点击此处< / a>'; 
 exit（）; 
} 
} 
 
 
 
 
？> 
<！DOCTYPE html PUBLIC -  // W3C // DTD XHTML 1.0 Transitional // ENhttp://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd\"> 
< html xmlns =http://www.w3.org/1999/xhtml> 
< head> 
< meta http-equiv =Content-Typecontent =text / html; charset = utf-8/> 
< title> AdminLogin< / title> 
< link rel =stylesheethref =../ style / style.csstype =text / cssmedia =screen/> 
< / head> 
 
< body> 
< div id =mainWrapper> 
<？php include_once（../ template_header.php）;？> 
< div id =pageContent> 
< div align =leftstyle =margin-left：040px;>< h1>请先登录才能继续< / h1>< br /> 
< / div> 
< form id =form1name =form1method =postaction =admin_login.php> 
 UserName< br /> 
< input type =textname =usernameid =usernamesize =40/> 
 Password< br /> 
< input type =passwordname =password id =passwordsize =40/> 
< br /> 
< br /> 
< br /> 
< input type =submitname =buttonid =buttonvalue =LogIn/> 
< / form> 
< / div> 
<？php include_once （../template_header.php\");?> 
< / div> 
< / body> 
< / html> 
 //index.php 
<？php 
 session_start（）; 
 if（！isset（$ _ SESSION [member]））{
 header（location：admin_login.php）; 
 exit（）; 
} 
 
 $ managerID = preg_replace（'＃[^ 0-9] #i'，，$ _ SESSION [id]）; 
 $ manager = preg_replace（'＃[A-Za-z0-9] #i'，，$ _ SESSION [manager]）; 
 $ password = preg_replace（'＃[A-Za-z0-9] #i'，'，$ _ SESSION [password]）; 
 
 
包括../storescripts/connect_to_mysql.php; 
 $ sql = mysql_query（SELECT * FROM admin WHERE id ='managerID'AND username ='$ manager'AND password ='$ password'LIMIT 1）; 
 $ exists_count = mysql_num_rows（$ sql）; 
 if（$ exists_count == 0）{
 echo（您的登录会话数据不在数据库中）; 
 exit（）; 
} 
 
 
 
？> 
<！DOCTYPE html PUBLIC -  // W3C // DTD XHTML 1.0 Transitional // ENhttp://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd\"> 
< html xmlns =http://www.w3.org/1999/xhtml> 
< html> 
< head> 
< meta http-equiv =Content-Typecontent =text / html; charset = utf-8/> 
< title>服务管理区域< / title> 
< link rel =stylesheethref =../ style / style.csstype =text / cssmedia =screen/> 
< / head> 
 
< body> 
< div id =mainWrapper> 
<？php include_once（../ template_header.php）;？> 
< div id =pageContent> 
< div align =leftstyle =margin-left：040px;>< h1> Hello Store Manager。您今天愿意做什么< / h1>< br / 
< h3>< a href =inventory_list.php>管理库存< / a>< / h3>< br />< h3>< a href =管理我< / a>< / h3>< br />< / div>< / div> 
<？php include_once（../ template_header.php）;？& 
< / div> 
< / body> 
< / html> 
  

b $ b

我面临的问题是，我不能登录到我的 index.php 页面，即使我已经输入正确的用户名和密码后，指定在我的数据库中，我通过phpmyadmin设置每次我尝试登录它调用 echo'这信息不正确，再试一次点击这里如<$

解决方案

>

尝试一些调试;

• 先检查$ _POST ['username']和$ _POST ['password']的值


• 在您对mysql_query（）的调用中添加'or die mysql_error（）'，看看是否运行正常


• 回显$ sql的值，以便查看查询。


• header（）命令不需要在名称和值之间有空格？或者\r\\\
  之后？值得仔细检查。


• 通常在各个阶段提供更多的输出，而且应该很少跟踪问题。

并且（一旦工作），请在数据库的密码字段中添加一个crypt（）或md5（）+ salt。

Possible Duplicate:
Undefined index: username in C:\wamp\www\Website\storeadmin\admin_login.php..and the same for password

//admin_login.php
<?php
session_start();
if(isset($_SESSION["member"])){
    header("location:index.php");
    exit();
}

?>
<?php
if(isset($_POST["username"]) && isset($_POST["password"])){     // <-  Check the user has clicked the button
  $manager = preg_replace('#[A-Za-z0-9]#i',"",$_POST["username"]);
  $password = preg_replace('#[A-Za-z0-9]#i',"",$_POST["password"]);



include "../storescripts/connect_to_mysql.php";
$sql = mysql_query("SELECT * FROM admin WHERE username ='$manager' AND password ='$password'LIMIT 1");
$exist_count = mysql_num_rows($sql);
if($exist_count == 1){
    while(mysql_fetch_array($sql)){
        $id = $row["id"];
        }

    $_SESSION["id"]= $id;
    $_SESSION["manager"]= $manager;
    $_SESSION["password"]= $password;
    header("location:index.php");
    exit();

    }
    else{
    echo 'This information is incorrect,try again <a href = "index.php">Click Here</a>';
    exit();
    }
}




?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title> AdminLogin</title>
<link rel="stylesheet" href="../style/style.css" type="text/css" media="screen"/>
</head>

<body>
<div  id="mainWrapper" > 
    <?php include_once("../template_header.php");?>
    <div id="pageContent" > 
    <div align="left" "style="margin-left:040px;"><h1>Please login to continue</h1><br />
    </div>
    <form id="form1" name="form1" method="post" action="admin_login.php"> 
    UserName<br />
    <input type="text" name="username" id="username" size="40"/>
    Password<br />
    <input type="password" name="password" id="password" size="40"/> 
    <br />
    <br />
    <br /> 
    <input type="submit" name="button" id="button" value="LogIn"/>  
    </form>
    </div>
    <?php include_once("../template_header.php");?>
</div>
</body>
</html>
//index.php
<?php
session_start();
if(!isset($_SESSION["member"])){
    header("location:admin_login.php");
    exit();
}

$managerID = preg_replace('#[^0-9]#i',"",$_SESSION["id"]);
$manager = preg_replace('#[A-Za-z0-9]#i',"",$_SESSION["manager"]);
$password = preg_replace('#[A-Za-z0-9]#i',"",$_SESSION["password"]);


include "../storescripts/connect_to_mysql.php";
$sql = mysql_query("SELECT * FROM admin WHERE id ='managerID' AND username ='$manager' AND password ='$password'LIMIT 1");
$exist_count = mysql_num_rows($sql);
if($exist_count == 0){
    echo("Your login session data in not in the database");
    exit();
}



?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<html >
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Service Admin Area</title>
<link rel="stylesheet" href="../style/style.css" type="text/css" media="screen"/>
</head>

<body>
<div  id="mainWrapper" > 
    <?php include_once("../template_header.php");?>
    <div id="pageContent" > 
    <div align="left" "style="margin-left:040px;"><h1>Hello Store Manager .What would you loke to do today</h1><br />
    <h3><a href="inventory_list.php">Manage Inventory</a></h3><br/><h3><a href="">Manage Me</a></h3><br/></div></div>
    <?php include_once("../template_header.php");?>
</div>
</body>
</html>

The problem I am facing is that I am not able to login to my index.php page even after I have put in the correct username and password as specified in my database which I have set through phpmyadmin. Everytime I try to login it invokes the echo 'This information is incorrect,try again Click Here' as mentioned in the admin_login.php. I am getting a bit frustrated. Can you help me out guys?

解决方案

Try some debugging;

• Check the values of $_POST['username'] and $_POST['password'] before and after your preg_replace calls.
• Add an 'or die mysql_error()' to your call to mysql_query() to see if that is running ok
• Echo out the value of $sql so you can have a look at the query.
• Does the header() command not require a space between the name and value? or a \r\n afterwards? Worth double-checking.
• Generally provide more output at various stages and it should be trivial to track down the issue.

And (once it is working), please please add a crypt() or md5() + salt to your password field in the database.

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