rbind两个data.frame保留行顺序和行名 [英] rbind two data.frame preserving row order and row names
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问题描述
我有一个 data.frame
对象的列表,我想将行附加到彼此,即 merge(...,all = T)
。但是, merge
似乎删除了我需要保持原样的行名称。有任何想法吗?示例:
I have a list of data.frame
objects which i would like to row append to one another, ie merge(..., all=T)
. However, merge
seems to remove the row names which I need to be kept intact. Any ideas? Example:
x = data.frame(a=1:2, b=2:3, c=3:4, d=4:5, row.names=c("row_1", "another_row1"))
y = data.frame(a=c(10,20), b=c(20,30), c=c(30,40), row.names=c("row_2", "another_row2"))
> merge(x, y, all=T, sort=F)
a b c d
1 1 2 3 4
2 2 3 4 5
3 10 20 30 NA
4 20 30 40 NA
推荐答案
既然你知道你实际上不是合并,但只是rbinding,也许这样的事情可以工作。它使用plyr中的 rbind.fill
。要使用它,请指定要$ rbind
data.frame
的列表
/ code>。
Since you know you are not actually merging, but just rbind-ing, maybe something like this will work. It makes use of rbind.fill
from "plyr". To use it, specify a list
of the data.frame
s you want to rbind
.
RBIND <- function(datalist) {
require(plyr)
temp <- rbind.fill(datalist)
rownames(temp) <- unlist(lapply(datalist, row.names))
temp
}
RBIND(list(x, y))
# a b c d
# row_1 1 2 3 4
# another_row1 2 3 4 5
# row_2 10 20 30 NA
# another_row2 20 30 40 NA
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