以编程方式向datagrid添加列不进行编译 [英] Programmatically add columns to datagrid not compiling

问题描述

这是继续

任何人都可以解释为什么？ p>

---编辑---

我现在意识到我误解了上面的链接。
简而言之，我有一个datagrid绑定到一个observable集合。
我必须再添加两列。如何做？

--- EDIT2 ---- CBreeze

  dtgResults.ItemsSource = obcmMyDim;< --------此前的数据
 DataGridTextColumn textColumn1 = new DataGridTextColumn（）; 
 textColumn1.Header =AAA1; 
 textColumn1.Binding = new Binding（AAA1）; 
 
 DataGridTextColumn textColumn2 = new DataGridTextColumn（）; 
 textColumn2.Header =AAA2; 
 textColumn2.Binding = new Binding（AAA2）; 
 
 Application.Current.Dispatcher.BeginInvoke（new ThreadStart（（）=> dtgResults.Columns.Add（textColumn1）））; 
 Application.Current.Dispatcher.BeginInvoke（new ThreadStart（（）=> dtgResults.Columns.Add（textColumn2）））; 
 
 dtgResults.Items.Add（new {AAA1 =Col1Row1，AAA2 =Col2Row1}）; 
 dtgResults.Items.Add（new {AAA1 =Col1Row2，AAA2 =Col2Row2}）; 
  

---编辑3 ---为JH
所以简而言之，绑定到datagrid的集合产生以下输出：

然后我用你的方法添加列：

  var names = obcmMyDim.First（）。obcItemsName; //所有条目必须具有相同的obcItemsName列表，并且按照相同的顺序
（int i = 0; i< names.Count; i ++）
 {
 DataGridTextColumn c = new DataGridTextColumn （）; 
 c.Header = names [i]; 
 
 var b = new Binding（）; 
 string str = string.Format（obcmMyDim.obcItemsMeasured [{0}]，i）; 
 b.Path = new PropertyPath（str）; 
 b.Mode = BindingMode.TwoWay; 
 
 c.Binding = b; 
 
 dtgResults.Columns.Add（c）; 
} 
  

对于绑定数组

，bind str是obcmMyDim.obcItemsMeasured [0]... 1 .... n

但是我得到的是列是在那里，但它们是空的

解决方案

你有没有尝试像

  dtgResults.Columns.Add（new DataGridTextColumn {标题=a.1}）; 
 dtgResults.Columns.Add（new DataGridTextColumn {Header =a.2}）; 
  

编辑：

（int i = 1; i< = 10; i ++）
{
dtgResults.Items.Add（new {a.1 =Test + i，a.2 =Test+ i}）;
}

This is the continuation to

OnEvent datagrid column add fail

I have seen this post:

How to add Data to a WPF datagrid programatically

the datagrid is simply this:

<DataGrid Name="dtgResults" Background="Transparent" AutoGenerateColumns="False"/>

in which everything seems to work fine but when I put it in my solution it doesn't compile:

Can anyone explain me why?

---EDIT---

I realize now that I have misunderstood what's in the link above. In short I have a datagrid binded to an observable collection. I have to add two more columns. How can that be done?

---EDIT2---- for CBreeze

 dtgResults.ItemsSource = obcmMyDim;<--------previous data here
 DataGridTextColumn textColumn1 = new DataGridTextColumn();
 textColumn1.Header = "AAA1";
 textColumn1.Binding = new Binding("AAA1");

 DataGridTextColumn textColumn2 = new DataGridTextColumn();
 textColumn2.Header = "AAA2";
 textColumn2.Binding = new Binding("AAA2");

 Application.Current.Dispatcher.BeginInvoke(new ThreadStart(() => dtgResults.Columns.Add(textColumn1)));
 Application.Current.Dispatcher.BeginInvoke(new ThreadStart(() => dtgResults.Columns.Add(textColumn2)));

 dtgResults.Items.Add(new { AAA1 = "Col1Row1", AAA2 = "Col2Row1"});
 dtgResults.Items.Add(new { AAA1 = "Col1Row2", AAA2 = "Col2Row2" });

---EDIT 3--- for JH So in short I have that observable collection which binded to the datagrid make the following output:

then I add the columns with your method:

var names = obcmMyDim.First().obcItemsName; // All entries must have the same list of obcItemsName and in the same order
    for (int i = 0; i < names.Count; i++)
    {
      DataGridTextColumn c = new DataGridTextColumn();
      c.Header = names[i];

      var b = new Binding();
      string str = string.Format("obcmMyDim.obcItemsMeasured[{0}]", i);
      b.Path = new PropertyPath(str);
      b.Mode = BindingMode.TwoWay;

      c.Binding = b;

      dtgResults.Columns.Add(c);
    }

as for the binded array

and the bind str is "obcmMyDim.obcItemsMeasured[0]" ...1....n

but what I get is that the columns are there but they are empty

解决方案

Have you tried something like;

dtgResults.Columns.Add(new DataGridTextColumn { Header = "a.1"});
dtgResults.Columns.Add(new DataGridTextColumn { Header = "a.2"});

EDIT:

 for (int i = 1; i <= 10; i++)
 {
     dtgResults.Items.Add(new { a.1 = "Test" + i, a.2 = "Test" + i});
 }

这篇关于以编程方式向datagrid添加列不进行编译的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！