在python中将不平等的列表压缩到不会将任何元素从较长列表中删除的列表中 [英] Zipping unequal lists in python in to a list which does not drop any element from longer list being zipped

问题描述

我有两个列表

a = [1,2,3]
b = [9,10]

我想将这两个列表组合（zip）到一个列表中 c ，使得

I want to combine (zip) these two lists into one list c such that

c = [(1,9), (2,10), (3, )]

Python中的标准库中是否有任何功能？

Is there any function in standard library in Python to do this?

推荐答案

您要寻求的是 itertools.izip_longest

What you seek is itertools.izip_longest

>>> a = [1,2,3]
>>> b = [9,10]
>>> for i in itertools.izip_longest(a,b): print i
... 
(1, 9)
(2, 10)
(3, None)

编辑1 ：如果你真的想摆脱无 s，那么你可以尝试：

EDIT 1: If you really want to get rid of the Nones, then you could try:

>>> for i in (filter(None, pair) for pair in itertools.izip_longest(a,b)): print i
(1, 9)
(2, 10)
(3,)

编辑2 ：回应steveha的评论：

EDIT 2: In response to steveha's comment:

filter(lambda p: p is not None, pair) for pair in itertools.izip_longest(a,b)

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