在Java中创建类似数据结构的结构 [英] Creating struct like data structure in Java

问题描述

我对Java很新，我试图找出一种在C中存储信息的方式来存储一个struct。例如，我想要一个程序雇用员工。它将从用户获取名字，姓氏和身份证号码，并将其存储。然后，用户可以根据条件查看该信息（例如，如果数据库具有超过1名员工）。可以任何建议最好的方法吗？

解决方案

C中的结构就像Java中的一个类，功能更强大，因为Java中的类可以包含方法，而C ++则可以。你创建一个新的类。例如：

  class Employee {
 private String name; 
私有int代码; 
 
 //构造函数
 public Employee（String name，int code）{
 this.name = name; 
 this.code = code; 
} 
 
 // getter 
 public String getName（）{return name; } 
 public int getCode（）{return code; } 
 // setter 
 
 public void setName（String name）{this.name = name; } 
 public void setCode（int code）{this.code = code; } 
} 
  

当你想创建多个员工时，像C中一样创建数组：

 员工[] arr = new Employee [100]; // new表示创建数组对象
 arr [0] = new Employee（Peter，100）; // new表示创建一个员工对象
 arr [1] = new Employee（Mary，90）; 
  

I am new to Java and I am trying to find out a way to store information like a struct in C. Say for example I want to have a program hire employees. It would take from the user a first name, last name, and id number and would store it. The user could then view that information based off a condition (if the database had more than 1 employee for example). Can any suggest the best way for doing this?

解决方案

A struct in C just like a class in Java and much more powerful, because class in Java can contain method, and C++ does. You create a new class. For example :

   class Employee {
       private String name;
       private int code;

   // constructor
   public Employee(String name, int code) {
      this.name = name;
      this.code = code;
   }

       // getter
       public String getName() { return name; }
       public int getCode() { return code; }
       // setter

       public void setName(String name) { this.name = name; }
       public void setCode(int code) { this.code = code; }
    }

And when you want to create multi employees, create array just like in C:

Employee[] arr = new Employee[100];  // new stands for create an array object
arr[0] = new Employee("Peter", 100); // new stands for create an employee object
arr[1] = new Employee("Mary", 90);

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