给定轴上的所有系列必须具有相同的数据类型 [英] All series on a given axis must be of the same data type
问题描述
这是目标,日期和时间: http://jsbin.com/ yaqew / 1 / edit
由于我已被通知,Google图表构造函数不会接受时间/日期字符串: https://developers.google.com/chart/interactive/docs/reference#dataparam
数据库:
PHP:
<?php
$ con = mysql_connect(localhost,root,)或die(无法连接数据库!!!!);
mysql_select_db(chart,$ con);
$ sth = mysql_query(SELECT * FROM googlechart);
$ rows = array();
//不需要标志
$ flag = true;
$ table = array();
$ table ['cols'] = array(
array('label'=>'Time','type'=>'datetime'),
数组('label'=>'Date','type'=>'datetime'),
数组('label'=>'PH','type'=& ''),
array('label'=>'temperature','type'=>'number'),
array('label'=>'Chlorine','type'= "'number'),
);
$ rows = array();
while($ r = mysql_fetch_assoc($ sth)){
//假定日期格式为yyyy-MM-dd
$ dateString = $ r ['Date'];
$ dateArray = explode(' - ',$ dateString);
$ year = $ dateArray [0];
$ month = $ dateArray [1] - 1; // subtract 1 to convert to javascript's 0-indexed months
$ day = $ dateArray [2];
echo $ dateString。< br>;
//假定时间格式为hh:mm:ss
$ timeString = $ r ['Time'];
$ timeArray = explode(':',$ timeString);
$ hours = $ timeArray [0];
$ minutes = $ timeArray [1];
$ seconds = $ timeArray [2];
echo $ timeString;
$ temp = array();
$ temp [] = array('v'=>Date($ year,$ month,$ day,$ hours,$ minutes,$ seconds));
$ temp [] = array('v'=>(string)$ r ['PH']);
$ temp [] = array('v'=>(string)$ r ['temperature']);
$ temp [] = array('v'=>(string)$ r ['Chlorine']);
$ rows [] = array('c'=> $ temp);
}
$ table ['rows'] = $ rows;
$ jsonTable = json_encode($ table);
/ * echo $ jsonTable; * /
?>
Html / Javascript:
< script type =text / javascriptsrc =https://www.google.com/jsapi>< / script>
< script type =text / javascript>
google.load(visualization,1,{packages:[corechart]});
google.setOnLoadCallback(drawChart);
函数drawChart(){
var data = new google.visualization.DataTable(<?= $ jsonTable?>);
var options = {
/ * width:900,height:900,* /
title:'Visualization',
curveType:'function',
legend:{position:'bottom'},
pointSize:12,
vAxis:{title:Values,titleTextStyle:{italic:false}},
hAxis:{title:Time,titleTextStyle:{italic:false}},
explorer:{
actions:['dragToZoom','rightClickToReset'],
轴:'vertical'
}
};
var chart = new google.visualization.LineChart(document.getElementById('chart_div'));
chart.draw(data,options);
}
p>您的列定义不正确:您只需要1列日期&时间,而不是两个:
$ table ['cols'] = array(
array('label'=> ;'日期和时间','type'=>'datetime'),
数组('label'=>'PH','type'=>'number'),
array('label'=>'temperature','type'=>'number'),
array('label'=>'Chlorine','type'=>'number' b $ b);
I early had problems with formatting the time, but now having problem with showing the google chart visualiszation out of this error: All series on a given axis must be of the same data type.
This is the goal, with date and time: http://jsbin.com/yaqew/1/edit
As I have been notified the google chart constructor will not accept the time/date string: https://developers.google.com/chart/interactive/docs/reference#dataparam
Database:
PHP:
<?php
$con=mysql_connect("localhost","root","") or die("Failed to connect with database!!!!");
mysql_select_db("chart", $con);
$sth = mysql_query("SELECT * FROM googlechart");
$rows = array();
//flag is not needed
$flag = true;
$table = array();
$table['cols'] = array(
array('label' => 'Time', 'type' => 'datetime'),
array('label' => 'Date', 'type' => 'datetime'),
array('label' => 'PH', 'type' => 'number'),
array('label' => 'temperature','type' => 'number'),
array('label' => 'Chlorine','type' => 'number'),
);
$rows = array();
while($r = mysql_fetch_assoc($sth)) {
// assumes dates are in the format "yyyy-MM-dd"
$dateString = $r['Date'];
$dateArray = explode('-', $dateString);
$year = $dateArray[0];
$month = $dateArray[1] - 1; // subtract 1 to convert to javascript's 0-indexed months
$day = $dateArray[2];
echo $dateString."<br>";
// assumes time is in the format "hh:mm:ss"
$timeString = $r['Time'];
$timeArray = explode(':', $timeString);
$hours = $timeArray[0];
$minutes = $timeArray[1];
$seconds = $timeArray[2];
echo $timeString;
$temp = array();
$temp[] = array('v' => "Date($year, $month, $day, $hours, $minutes, $seconds)");
$temp[] = array('v' => (string) $r['PH']);
$temp[] = array('v' => (string) $r['temperature']);
$temp[] = array('v' => (string) $r['Chlorine']);
$rows[] = array('c' => $temp);
}
$table['rows'] = $rows;
$jsonTable = json_encode($table);
/* echo $jsonTable; */
?>
Html/Javascript:
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load("visualization", "1", {packages:["corechart"]});
google.setOnLoadCallback(drawChart);
function drawChart() {
var data = new google.visualization.DataTable(<?=$jsonTable?>);
var options = {
/*width: 900, height: 900, */
title: 'Visualization',
curveType: 'function',
legend: { position: 'bottom' },
pointSize: 12,
vAxis: {title: "Values", titleTextStyle: {italic: false}},
hAxis: {title: "Time", titleTextStyle: {italic: false}},
explorer: {
actions: ['dragToZoom', 'rightClickToReset'],
axis: 'vertical'
}
};
var chart = new google.visualization.LineChart(document.getElementById('chart_div'));
chart.draw(data, options);
}
Your column definitions are not correct: you want only 1 column for date & time, not two:
$table['cols'] = array(
array('label' => 'Date & Time', 'type' => 'datetime'),
array('label' => 'PH', 'type' => 'number'),
array('label' => 'temperature','type' => 'number'),
array('label' => 'Chlorine','type' => 'number')
);
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